Problem 2 - 51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po = 90 kPa ethyl alcohol p = 773.3 kg/m? 60 m oil 10 m p = 899.6 kg/m³ water 5 m p = 979 kg/m³ glycerin p = 1236 kg/m 5 m

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Chapter10: Force And Force-related Variables In Engineering
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Problem 2 - 51
In Figure 13, in which fluid will a pressure of 700 kPa first be achieved?
Ans: glycerin
Po = 90 kPa
ethyl alcohol
p = 773.3 kg/m?
60 m
oil
10 m
p = 899.6 kg/m3
water
5 m
p = 979 kg/m³
glycerin
p= 1236 kg/m
5 m
Transcribed Image Text:Problem 2 - 51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po = 90 kPa ethyl alcohol p = 773.3 kg/m? 60 m oil 10 m p = 899.6 kg/m3 water 5 m p = 979 kg/m³ glycerin p= 1236 kg/m 5 m
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