9.2 Problem 2: You have been hired to design a family-friendly see-saw. Your design willfeature a uniform board (mass M = 13 kg, length L = 8 m) that can be moved so thatthe pivot is a distance d from the center of the board. This will allow riders to achievestatic equilibrium even if they are of different mass, as most people are. You havedecided that each rider will be positioned so that his/her center of mass will be adistance xoffset = 29 cm from the end of the board when seated as shown.You have selected a child of mass m = 25 kg (shown on the right), and an adult of massn =4 times the mass of the child (shown on the left) to test out your prototype.XoffsetXoffsetPart (a) Determine the distance d in m.Numeric : A numeric value is expected and not an expression.d =Part (b) Determine the magnitude of the force exerted on the pivot point by the see-saw in N.Numeric : A numeric value is expected and not an expression.F =

Answered: Image /qna-images/answer/8f5d1916-3ea0-4415-b81a-84dc72e0172b.jpg

Problem 2: You have been hired to design a family-friendly see-saw. Your design will feature a uniform board (mass M = 13 kg, length L = 8 m) that can be moved so that the pivot is a distance d from the center of the board. This will allow riders to achieve static equilibrium even if they are of different mass, as most people are. You have decided that each rider will be positioned so that his/her center of mass will be a distance xoffser = 29 cm from the end of the board when seated as shown. You have selected a child of mass m = 25 kg (shown on the right), and an adult of mass n =4 times the mass of the child (shown on the left) to test out your prototype. Xffset Xoffset Part (a) Determine the distance d in m. Numeric : Anumeric value is expected and not an expression. d = Part (b) Determine the magnitude of the force exerted on the pivot point by the see-saw in N. Numeric : A numeric value is expected and not an expression. F, =

Problem 2: You have been hired to design a family-friendly see-saw. Your design will feature a uniform board (mass M = 13 kg, length L = 8 m) that can be moved so that the pivot is a distance d from the center of the board. This will allow riders to achieve static equilibrium even if they are of different mass, as most people are. You have decided that each rider will be positioned so that his/her center of mass will be a distance xoffser = 29 cm from the end of the board when seated as shown. You have selected a child of mass m = 25 kg (shown on the right), and an adult of mass n =4 times the mass of the child (shown on the left) to test out your prototype. Xffset Xoffset Part (a) Determine the distance d in m. Numeric : Anumeric value is expected and not an expression. d = Part (b) Determine the magnitude of the force exerted on the pivot point by the see-saw in N. Numeric : A numeric value is expected and not an expression. F, =

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter10: Rotational Motion

Section: Chapter Questions

Problem 74P: A stepladder of negligible weight is constructed as shown in Figure P10.73, with AC = BC = ℓ. A...

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A stepladder of negligible weight is constructed as shown in Figure P10.73, with AC = BC = = 4.00 m. A painter of mass m = 70.0 kg stands on the ladder d = 3.00 m from the bottom. Assuming the floor is frictionless, find (a) the tension in the horizontal bar DE connecting the two halves of the ladder, (b) the normal forces at A and B, and (c) the components of the reaction force at the single hinge C that the left half of the ladder exerts on the right half. Suggestion: Treat the ladder as a single object, but also treat each half of the ladder separately.
A stepladder of negligible weight is constructed as shown in Figure P10.73, with AC = BC = ℓ. A painter of mass m stands on the ladder a distance d from the bottom. Assuming the floor is frictionless, find (a) the tension in the horizontal bar DE connecting the two halves of the ladder, (b) the normal forces at A and B, and (c) the components of the reaction force at the single hinge C that the left half of the ladder exerts on the right half. Suggestion: Treat the ladder as a single object, but also treat each half of the ladder separately. Figure P10.73 Problems 73 and 74.
Why is the following situation impossible? A uniform beam of mass mk = 3.00 kg and length = 1.00 m supports blocks with masses m1 = 5.00 kg and m2 = 15.0 kg at two positions as shown in Figure P12.2. The beam rests on two triangular blocks, with point P a distance d = 0.300 m to the right of the center of gravity of the beam. The position of the object of mass m2 is adjusted along the length of the beam until the normal force on the beam at O is zero. Figure P12.2
Consider a nanotube with a Youngs modulus of 2.130 1012 N/m2 that experiences a tensile stress of 5.3 1010 N/m2. Steel has a Youngs modulus of about 2.000 1011 Pa. How much stress would cause a piece of steel to experience the same strain as the nanotube?
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A uniform plank of length 5 m and weight 200 N rests horizontally on two supports with 1.1 m of the plank hanging over the right support. To what distance x, can a person who weights 430 N walk on the overhanging part of the plank before it just starts to tip? What is the net torque around the pivot point (take the FR support as the pivot point)?