PROBLEM 3: Consider the following cable system: cables AE, BE, CE, and DE intersect at point E. The coordinates of A, B, C and E are given: A (-2, 3, 2) m B (0, -2,5) m C (-3, 3, -1) m E (4, Y, 1) m Projection angles of D are 0 = 24°, and a = 10°, and distance L = 6 m. The length of cable AE is 4.8 m. Note the at D is on plane x-z. The forces in each cable are: EA = 122 KN EB = 111 KN EC = 95 KN FD=108 KN

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter3: Resultants Of Force Systems
Section: Chapter Questions
Problem 3.55P: The concrete pier is subjected to soil pressure that causes the line loads shown. Determine the...
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N
B
A
Y
E
Ja
L
с
8
D
X
Required: DO NOT INCLUDE (-) NEGATIVE SIGN IN ANY OF YOUR ANSWERS FOR ITEMS BELOW.
1. Calculate the x-component of force EA =
KN use 2 decimal places
2. Calculate the y-component of the resultant =
3. Calculate the magnitude of the resultant =
4. Calculate the spatial angle of the resultant from x-axis =
5. Calculate the spatial angle of the resultant from y-axis =
KN use 2 decimal places
KN use 2 decimal places
use 2 decimal places
use 2 decimal places
Transcribed Image Text:N B A Y E Ja L с 8 D X Required: DO NOT INCLUDE (-) NEGATIVE SIGN IN ANY OF YOUR ANSWERS FOR ITEMS BELOW. 1. Calculate the x-component of force EA = KN use 2 decimal places 2. Calculate the y-component of the resultant = 3. Calculate the magnitude of the resultant = 4. Calculate the spatial angle of the resultant from x-axis = 5. Calculate the spatial angle of the resultant from y-axis = KN use 2 decimal places KN use 2 decimal places use 2 decimal places use 2 decimal places
PROBLEM 3: Consider the following cable system: cables AE, BE, CE, and DE intersect at point E. The coordinates of A, B, C and E are given:
A (-2, 3, 2) m
B (0, -2,5) m
C (-3, 3, -1) m
E (4, Y, 1) m
Projection angles of D are 0 = 24°, and a = 10⁰, and distance L = 6 m. The length of cable AE is 4.8 m. Note the at D is on plane x-z.
The forces in each cable are:
EA = 122 KN
EB = 111 KN
EC = 95 KN
ED = 108 KN
Transcribed Image Text:PROBLEM 3: Consider the following cable system: cables AE, BE, CE, and DE intersect at point E. The coordinates of A, B, C and E are given: A (-2, 3, 2) m B (0, -2,5) m C (-3, 3, -1) m E (4, Y, 1) m Projection angles of D are 0 = 24°, and a = 10⁰, and distance L = 6 m. The length of cable AE is 4.8 m. Note the at D is on plane x-z. The forces in each cable are: EA = 122 KN EB = 111 KN EC = 95 KN ED = 108 KN
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