Problem 3: Two mirrors are placed perpendicular to each other. A beam of light reflects off mirror 1 with incident angle 0; = 72 degrees, then reflects off mirror 2 with angle Of 02 Of Part (a) If the angle the light reflected from mirror 1 is 01, express 0, in terms of 0₁. Expression : 01 Select from the variables below to write your expression. Note that all variables may not be required. a, ß, 0₁, a, d, g, h, i, j, k, m, P, S, t, z Part (b) If the incident angle of the light on mirror 2 is 02, express 02 in terms of 0₁. Expression : 02 1 011 0₁

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Chapter1: Units, Trigonometry. And Vectors
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Problem 3: Two mirrors are placed perpendicular to each other. A beam of light
reflects off mirror 1 with incident angle 0; = 72 degrees, then reflects off mirror 2 with
angle Of
Part (a) If the angle the light reflected from mirror 1 is 01, express , in terms of 0₁.
Expression :
0₁ =
01
Select from the variables below to write your expression. Note that all variables may not be required.
a, ß, 0₁, a, d, g, h, i, j, k, m, P, S, t, z
Part (b) If the incident angle of the light on mirror 2 is 02, express 02 in terms of 0₁.
Expression :
0₂=
02
Of
0₁ Oi
Transcribed Image Text:Problem 3: Two mirrors are placed perpendicular to each other. A beam of light reflects off mirror 1 with incident angle 0; = 72 degrees, then reflects off mirror 2 with angle Of Part (a) If the angle the light reflected from mirror 1 is 01, express , in terms of 0₁. Expression : 0₁ = 01 Select from the variables below to write your expression. Note that all variables may not be required. a, ß, 0₁, a, d, g, h, i, j, k, m, P, S, t, z Part (b) If the incident angle of the light on mirror 2 is 02, express 02 in terms of 0₁. Expression : 0₂= 02 Of 0₁ Oi
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