Problem 3: Using constant acceleration equations for motion in free fall A rock is thrown straight up from a 30 m cliff above the ground level with a speed of 20 On the way down it misses the cliff and continues all the way down to the ground level. The trajectory of the rock is shown by the black dashed line in the figure. The free-fall acceleration has a magnitude of 10 and is directed downwards. E. What is the net displacement of the rock for its entire trajectory? Assume that the positive y-direction points up, as shown in the figure. F. Find the total time the rock is in the air. Express your answer in seconds. G. Find the rock's velocity in the y-direction v, exactly 5 seconds after it is thrown up. Use the usual sign convention (positive for up, negative for down). Express your answer in m/s.

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Displacement, Velocity and Acceleration

In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.

Linear Displacement

The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.