Problem 4: The puck in the figure above on the left has a mass of 0.120 kg. The distance of the puck from the center of rotation is originally 0.4 m, and the puck is sliding with a speed of v₁ = 0.8 m/sec. The string is pulled downward through the hole in the frictionless table and the new distance of the puck from the center of rotation is 0.25 m. What is the new speed of the puck? Answer: vf = 1.28 m/sec 09 R m

Problem 4: The puck in the figure above on the left has a mass of 0.120 kg. The distance of the puck from the center of rotation is originally 0.4 m, and the puck is sliding with a speed of v₁ = 0.8 m/sec. The string is pulled downward through the hole in the frictionless table and the new distance of the puck from the center of rotation is 0.25 m. What is the new speed of the puck? Answer: vf = 1.28 m/sec 09 R m