Problem 5: A particle of mass 0.15 kg is attached to a spring. The mass follows simple harmonic motion. The position of the particle, as a function of time, is given by the equation x(t)=0.30 cos (8.0t + 7). What is the spring constant of the spring? Answer: 9.6 N/m

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 20P: A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period...
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Problem 5:
A particle of mass 0.15 kg is attached to a spring. The mass follows simple harmonic motion.
The position of the particle, as a function of time, is given by the equation
x(t)=0.30 cos (8.0t +
7). What is the spring constant of the spring? Answer: 9.6 N/m
Transcribed Image Text:Problem 5: A particle of mass 0.15 kg is attached to a spring. The mass follows simple harmonic motion. The position of the particle, as a function of time, is given by the equation x(t)=0.30 cos (8.0t + 7). What is the spring constant of the spring? Answer: 9.6 N/m
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