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Problem 5: Suppose the ski patrol lowers a rescue sled carrying an injured skiier, with a combined mass of 77.5 kg, down a 60.0° slope at constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and the snow is 0.100. w 60° Part (a) How much work, in joules, is done by friction as the sled moves 32.5 m along the hill? Numeric : A numeric value is expected and not an expression. Wf =. Part (b) How much work, in joules, is done by the rope on the sled over this distance? Numeric : A numeric value is expected and not an expression. Wr = Part (c) What is the work, in joules, done by the gravitational force on the sled? Numeric : A numeric value is expected and not an expression. W. = Part (d) What is the net work done on the sled, in joules? Numeric : A numeric value is expected and not an expression. W = net

Problem 5: Suppose the ski patrol lowers a rescue sled carrying an injured skiier, with a combined mass of 77.5 kg, down a 60.0° slope at constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and the snow is 0.100. w 60° Part (a) How much work, in joules, is done by friction as the sled moves 32.5 m along the hill? Numeric : A numeric value is expected and not an expression. Wf =. Part (b) How much work, in joules, is done by the rope on the sled over this distance? Numeric : A numeric value is expected and not an expression. Wr = Part (c) What is the work, in joules, done by the gravitational force on the sled? Numeric : A numeric value is expected and not an expression. W. = Part (d) What is the net work done on the sled, in joules? Numeric : A numeric value is expected and not an expression. W = net

University Physics Volume 1
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter8: Potential Energy And Conservation Of Energy
Section: Chapter Questions
Problem 81AP: Repeat the preceding problem, but this time, suppose that the work done by air resistance cannot be...
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Please answer Question 5 parts b-d

Problem 5: Suppose the ski patrol lowers a rescue sled carrying an injured skiier, with a combined mass of 77.5 kg, down a 60.0° slope at constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and the snow is 0.100. 60° Part (a) How much work, in joules, is done by friction as the sled moves 32.5 m along the hill? Numeric : A numeric value is expected and not an expression. Wf = Part (b) How much work, in joules, is done by the rope on the sled over this distance? Numeric : A numeric value is expected and not an expression. Wr = Part (c) What is the work, in joules, done by the gravitational force on the sled? Numeric : A numeric value is expected and not an expression. Part (d) What is the net work done on the sled, in joules? Numeric : A numeric value is expected and not an expression. W net
Transcribed Image Text:Problem 5: Suppose the ski patrol lowers a rescue sled carrying an injured skiier, with a combined mass of 77.5 kg, down a 60.0° slope at constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and the snow is 0.100. 60° Part (a) How much work, in joules, is done by friction as the sled moves 32.5 m along the hill? Numeric : A numeric value is expected and not an expression. Wf = Part (b) How much work, in joules, is done by the rope on the sled over this distance? Numeric : A numeric value is expected and not an expression. Wr = Part (c) What is the work, in joules, done by the gravitational force on the sled? Numeric : A numeric value is expected and not an expression. Part (d) What is the net work done on the sled, in joules? Numeric : A numeric value is expected and not an expression. W net
Expert Solution
Step 1

mass of man skier and sled, m=77.5 Kg

displacement of   sled with skier, d=32.5 m

Coefficient of kinetic friction, μ=0.1

Angle of inclination, θ=600

Sled is moved with constant velocity.

 

Work done on an object :

W=F.x

where,

F=applied force on the object

x=displacement of the object

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