Problem #59 The subsoil profile of a proposed site of construction is shown below, a square footing of 2m x 2m carries a load of 1000 kN and is laid with its base at lm depth below ground surface assuming that post construction settlement in sand is negligible determine the consolidation settlement of clay layer on account of construction. There is geological evidence, clay is NC, use 2 vertical and 1 horizontal for load dispersion to estimate the stress increase in clay layer. 1000 KN Sand Y 16 kN/m³ 2 m W.T Wn = 40% GS = 2.7 W₁ = 60% Rock Soil Profile 2 m 3 m [Answer = 86.199mm] Sand Y = 20 kN/m³ Clay y 19 kN/m³

Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter16: Soil Bearing Capacity For Shallow Foundations
Section: Chapter Questions
Problem 16.14P: Redo Problem 16.13 with the following data: gross allowable load = 184,000 lb, = 121 lb/ft3, c = 0,...
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Problem #59
The subsoil profile of a proposed site of construction
is shown below, a square footing of 2m x 2m carries
a load of 1000 kN and is laid with its base at lm
depth below ground surface assuming that post
construction settlement in sand is negligible
determine the consolidation settlement of clay layer
on account of construction. There is geological
evidence, clay is NC, use 2 vertical and 1
horizontal for load dispersion to estimate the stress
increase in clay layer.
1000 KN
Sand
Y 16 kN/m³
2 m
W.T
Wn = 40%
GS = 2.7
W₁ = 60%
Rock Soil Profile
2 m
3 m
[Answer = 86.199mm]
Sand
Y = 20 kN/m³
Clay
y 19 kN/m³
Transcribed Image Text:Problem #59 The subsoil profile of a proposed site of construction is shown below, a square footing of 2m x 2m carries a load of 1000 kN and is laid with its base at lm depth below ground surface assuming that post construction settlement in sand is negligible determine the consolidation settlement of clay layer on account of construction. There is geological evidence, clay is NC, use 2 vertical and 1 horizontal for load dispersion to estimate the stress increase in clay layer. 1000 KN Sand Y 16 kN/m³ 2 m W.T Wn = 40% GS = 2.7 W₁ = 60% Rock Soil Profile 2 m 3 m [Answer = 86.199mm] Sand Y = 20 kN/m³ Clay y 19 kN/m³
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