Problem 6: The sides of a small rectangular box are measured to be 1.55 + 0.045 cm, 2.1 + 0.025cm, and 2.75 + 0.075 cm long. In this problem you can approximate the percent error on a product or quotient of quantities by the sum of the percent error on each quantity. Part (a) Calculate its volume in cm?. / Correct! V = 8.95 Part (b) Calculate its uncertainty in cm3. Oy = cm3

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Q: 4. Fill the Table 2 with the equivalent quantity by conversion the following physical quantities…

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A: Given physical quantity is, ML/T2

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A: Given data: Mass of the cube, m=12 g Measurements of the cube:  l=1.05 mm=0.105 cmb=1.25 mm=0.125…

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Q: When you perform the following operations, how many significant figures should your answer have?…

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A: A) Volume of pyramid: V = 13(area of base ×height)V = 13(10 acrea)(43560 ft21 acre)(488 ft)V = 70.85…

Q: P V =

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Q: Question 1.1: Express the following quantities in prefixes: (a) (b) (c) 3 x 10 4m 5 x 10-5s 72 x…

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Q: 128. Compute the relative error and absolute error when measuring the area of a rectangle of length,…

A: As per guidelines, only first , Q.138 is solved her. L = (10±0.2)m W = 6±0.1m We know that area =…

Q: Problem 16. Consider the physical quantities m, s, v, a, and t with dimensions [m] = M, [s] = L, [v]…

A: Given data:  The dimensions of m, s, v, a and [m] = M, [s] = L,  [v] = LT-1, [a] = LT-2 and [t]  = T…

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Q: How should the computed result be reported, to the proper number of significant figures, for the…

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Estimate of calculation