Problem: A bomb initially at rest on a smooth, horizontal surface is exploded into three pieces. Two pieces fly off horizontally at a 60° angle to each other, a 2.0 kg piece at 20 m/s and a 3.0 kg piece at 12 m/s. The third piece flies off horizontally at 30 m/s. (a) Determine the direction of motion of the third piece. (b) What is its mass?
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- The asnwer was incorrect and I recieved the following as feedback: "You may have used the nonrelativistic (low-speed) expression for momentum. That is not justified in the present case."If 2 marbles (of same mass and speed) travel from one end of a straight line runway and strike a line of marbles, is it possible to have only one marble to pop off the other end of the line at twice the speed? Why? (explain based on momentum and kinetic energy) I tried to find the momentum for the single marble and got 2mv and found the kinetic energy to be 2mv^2 but I'm not sure if it's right or how to how to explain it if it is possible or not.A proton has a total energy of 3 times its rest energy. What is the momentum of this proton? (in Me) Check correct answer show all work
- So far we have learned that the formula for Kinetic Energy is KE= 1/2mv2. However, for this lab, we would like to describe the motion of the objects using momentum. p=mv, instead of velocity. Using the two equations given, find a new formula for Kinetic Energy in terms of momentum not velocity. Based on the picture, which one is the correct answer?Calculate impulse and pulse given: mass: .009072kg max PE: .0889 max KE: .0889 max velocity: 4.42 drop time: .5 s find: impulse? Force? show work so i can understand please and thank you1.What is the final speed of particle 1? 2. What is the mass of the second particle? 3. what is the final speed of particle 2 *** please include the equations clearly so i can follow through
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- answer is not 0.44, I received this as feedback: You may have used the nonrelativistic (low-speed) expression for momentum. That is not justified in the present case.Consider the equation for kinetic energy: KE = 1/2mv^2 = 1/2 * m * v^2. If I ask you to take the derivative of kinetic energy, you should ask "the derivative with respect to what?" a) Suppose mass m is constant. Compute the derivative of KE with respect to v, (d(KE)/dv). b) Who takes derivatives with respect to velocity? No one. Except you, just now. Sorry. The rate of change of energy with respect to time is more important: it is the Power. Now, consider velocity v to be a function of time, v(t). We will rewrite KE showing this time dependance: KE= 1/2 * m * v(t)^2. Show that (d(KE)/dt) = F(t)v(t). Hint: use Newton's second law, F = ma, to simplify. c) In the computation above, we assumed m was constant, and v was changing in time. Think of a physical situation in which both m and v are varying in time. d) Compute the Power when both mass and velocity are changing in time. (First rewrite KE(t) showing time dependence, then compute (d(KE)/dt).can someone please do all sections of this question? show it step by step please and don't miss a part pleaseeee You get frustrated with your physics homework and you throw a blob of clay of mass m at a speed of vi at an angle of θ to the horizontal at your physics book of mass M that is sitting, sadly unread, on the floor. The clay sticks to the top of the book and the system slides a distance x along the floor before coming to a stop. a) State and justify whether or not linear momentum is conserved for the clay+book system i) in the x (horizontal) direction and ii) in the y (vertical) direction. (Hint: draw a sketch of the situation). b) Derive an expression for the coefficient of friction between the book and the floor in terms of the given quantities m, M vi,, θ, g, and x. c) Compute μk for m=65.0 g, M=1.50 kg, θ =30.0, vi = 20.0 m/s, d = 6.20 cm.