Problem Five. Now consider if the spherical insulator in problem Three (which has a radius R and a total charge Q on it) is surrounded by a conducting spherical shell with inner radius "a" and outer radius "2a." The conductor has a charge of 20 on it. 13. Find the charge remaining on the outer radius "2a" of the conductor. (A) 0 (B)-Q (C) Q (D) 70 (E) 30 14. Write an expression for the surface charge density on the inner surface of the conductor. (A) -Q 4π a² (B) Q 4π a² (C) -Q 75 8π a² (D) Σπαζ (E) 2a 20 πα

Physics for Scientists and Engineers: Foundations and Connections
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Publisher:Katz, Debora M.
Chapter25: Gauss’s Law
Section: Chapter Questions
Problem 68PQ: Examine the summary on page 780. Why are conductors and charged sources with linear symmetry,...
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Problem Five. Now consider if the spherical insulator in problem
Three (which has a radius R and a total charge Q on it)
surrounded by a conducting spherical shell with inner radius "a"
and outer radius "2a." The conductor has a charge of 20 on it.
13. Find the charge remaining on the outer radius "2a" of the
conductor.
(A) 0
(B)-Q (C) Q
(D) 70
(E) 30
14. Write an expression for the surface charge density on the
inner surface of the conductor.
-Q
(A)
4π a²
(B)
Q
4π a²
(C)
-Q
8π a²
(D)
-Q
2πατ
a
(E)
2a
20
παζ
Transcribed Image Text:Problem Five. Now consider if the spherical insulator in problem Three (which has a radius R and a total charge Q on it) surrounded by a conducting spherical shell with inner radius "a" and outer radius "2a." The conductor has a charge of 20 on it. 13. Find the charge remaining on the outer radius "2a" of the conductor. (A) 0 (B)-Q (C) Q (D) 70 (E) 30 14. Write an expression for the surface charge density on the inner surface of the conductor. -Q (A) 4π a² (B) Q 4π a² (C) -Q 8π a² (D) -Q 2πατ a (E) 2a 20 παζ
15. Write an expression for the surface charge density on the outer surface of the conductor.
Q
(A)
-Q
4π a²
(B)
(C)
30
16πα2
(D)
2πατ
For the region between the insulator and the conductor (R<r <a)...
16. Find the flux through a Gaussian surface.
(A) 0
(B) Q/&
Q
4πα?
17. Find the electric field.
(A) 0
(C) 7k,Q
(B)
For the region inside the conductor (a <r<2a)...
19. Find the electric field.
(A) 0
(B)
6k Q
18. Find the flux through a Gaussian surface.
(A) 0
(B) Q/E
(D)
9k₂Q
21. Find the electric field.
(A) 0
kQ2a³+5r³)
7a³r²
(C) - Q/&
20. Find the flux through a Gaussian surface.
(A) 0
(B) Q/&o
6k Q
(B)
For the region outside the conductor (r>2a)...
(C) - Q/&
(B)
(C)
)
(E)
8kQ
(C) - Q/E
7kQ
(C) 7h0
k₂Q(5a³ +7r³)
5a³r²
(D) 70/80
kQ(7a¹ +5r³)
2a³r²
8kQ
(D) 70/80
Q
D) 7k ₂0
(D)
(D) 70/80
3k Q
(D) 34,0
(C)
(E)
(E) 80/80
22. Now consider if the surrounding spherical shell is an insulator (rather than a conductor) but it still has
a charge of 20 uniformly distributed throughout it. Find the magnitude of the electric field in the
region (a <r<2a).
k.Q(7 a³ +2r³)
(A)
5a³r²
-30
16πα2
(E) 80/80
(E)
k₂Q(5a³ + 2r³)
7a³r²
kQ
k₂Q
(E) 30/80
kQ
(E)KO
Transcribed Image Text:15. Write an expression for the surface charge density on the outer surface of the conductor. Q (A) -Q 4π a² (B) (C) 30 16πα2 (D) 2πατ For the region between the insulator and the conductor (R<r <a)... 16. Find the flux through a Gaussian surface. (A) 0 (B) Q/& Q 4πα? 17. Find the electric field. (A) 0 (C) 7k,Q (B) For the region inside the conductor (a <r<2a)... 19. Find the electric field. (A) 0 (B) 6k Q 18. Find the flux through a Gaussian surface. (A) 0 (B) Q/E (D) 9k₂Q 21. Find the electric field. (A) 0 kQ2a³+5r³) 7a³r² (C) - Q/& 20. Find the flux through a Gaussian surface. (A) 0 (B) Q/&o 6k Q (B) For the region outside the conductor (r>2a)... (C) - Q/& (B) (C) ) (E) 8kQ (C) - Q/E 7kQ (C) 7h0 k₂Q(5a³ +7r³) 5a³r² (D) 70/80 kQ(7a¹ +5r³) 2a³r² 8kQ (D) 70/80 Q D) 7k ₂0 (D) (D) 70/80 3k Q (D) 34,0 (C) (E) (E) 80/80 22. Now consider if the surrounding spherical shell is an insulator (rather than a conductor) but it still has a charge of 20 uniformly distributed throughout it. Find the magnitude of the electric field in the region (a <r<2a). k.Q(7 a³ +2r³) (A) 5a³r² -30 16πα2 (E) 80/80 (E) k₂Q(5a³ + 2r³) 7a³r² kQ k₂Q (E) 30/80 kQ (E)KO
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