Problem In the lectures, we discussed how to use an NPN BJT as an emitter follower. In the circuit below, the emitter follower is connected to a non-ideal voltage source V with a source resistance R Assume beta = 100, V = 0.7 V, V = OV. BE CE,sat a. If R = 0 and V = 3 V, determine the value of V. S b. If R = 5k and V = 3 V, determine the value of V. S = 5k , determine the value of V that will cause the BJT to start c. If R saturating. +5V Rs Vs O- M 550 V₂ R₁=1K

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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In the lectures, we discussed how to use an NPN BJT as an emitter follower. In the circuit
below, the emitter follower is connected to a non-ideal voltage source V with a source
resistance R
Assume beta = 100, V
= 0.7 V, V
= OV.
BE
CE,sat
a. If R = 0 and V = 3 V, determine the value of V.
S
b. If R = 5k and V = 3 V, determine the value of V.
S
= 5k , determine the value of V that will cause the BJT to start
c. If R
saturating.
+5V
Rs
Vs O-
M
550
V₂
R₁=1K
Transcribed Image Text:Problem In the lectures, we discussed how to use an NPN BJT as an emitter follower. In the circuit below, the emitter follower is connected to a non-ideal voltage source V with a source resistance R Assume beta = 100, V = 0.7 V, V = OV. BE CE,sat a. If R = 0 and V = 3 V, determine the value of V. S b. If R = 5k and V = 3 V, determine the value of V. S = 5k , determine the value of V that will cause the BJT to start c. If R saturating. +5V Rs Vs O- M 550 V₂ R₁=1K
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