Problem2: Arrange electrically charged particles as shown below with d= 39.0 cm and the charge of each particle will be a number of times the charge 91 = 3.40 PC and q2 = 6.00 PC when the electric potential is set to be equal to zero at infinity. Calculate the following values. • (a) What is the net electric potential at the center (point P) of the rectangle? • (b) To transfer a charge of 43 = -3.40 pC from infinity to point P, how much work must we do? Explain the meaning of the calculated answer value (find the answer value from the change in electric potential energy AU) +291 d -91 ·d- -d. +492 + P +492 d d -3q1 d +291

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 18P: A positive point charge q = +2.50 nC is located at x = 1.20 m and a negative charge of 2q = 5.00 nC...
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Problem2: Arrange electrically charged particles as shown below with d= 39.0 cm and the charge of each particle will be a number of times
the charge 91 = 3.40 PC and q2 = 6.00 PC when the electric potential is set to be equal to zero at infinity. Calculate the following values.
• (a) What is the net electric potential at the center (point P) of the rectangle?
• (b) To transfer a charge of 43 = -3.40 pC from infinity to point P, how much work must we do? Explain the meaning of the calculated answer
value (find the answer value from the change in electric potential energy AU)
+291
d
-91
-d
d.
+492
+
•P
+
+492
·d.
d-
-391
d
+
+291
Transcribed Image Text:Problem2: Arrange electrically charged particles as shown below with d= 39.0 cm and the charge of each particle will be a number of times the charge 91 = 3.40 PC and q2 = 6.00 PC when the electric potential is set to be equal to zero at infinity. Calculate the following values. • (a) What is the net electric potential at the center (point P) of the rectangle? • (b) To transfer a charge of 43 = -3.40 pC from infinity to point P, how much work must we do? Explain the meaning of the calculated answer value (find the answer value from the change in electric potential energy AU) +291 d -91 -d d. +492 + •P + +492 ·d. d- -391 d + +291
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