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Program 4.6.1 #include using namespace std; int main () { int X = 5, Y = 15;  int * p1, * p2; p1 = &X; // p1 = address of X p2 = &Y; // p2 = address of Y *p1 = 10; // value pointed by p1 = 10 *p2 = *p1; // value pointed by p2 = value pointed by p1 p1 = p2; // p1 = p2 (value of pointer is copied) *p1 = 40; // value pointed by p1 = 20 cout << "X is " << X << endl; cout << "Y is " << Y << endl;

Program 4.6.1 #include using namespace std; int main () { int X = 5, Y = 15;  int * p1, * p2; p1 = &X; // p1 = address of X p2 = &Y; // p2 = address of Y *p1 = 10; // value pointed by p1 = 10 *p2 = *p1; // value pointed by p2 = value pointed by p1 p1 = p2; // p1 = p2 (value of pointer is copied) *p1 = 40; // value pointed by p1 = 20 cout << "X is " << X << endl; cout << "Y is " << Y << endl;

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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// Program 4.6.1


#include <iostream>
using namespace std;
int main ()
{
int X = 5, Y = 15;
 int * p1, * p2;
p1 = &X; // p1 = address of X
p2 = &Y; // p2 = address of Y
*p1 = 10; // value pointed by p1 = 10
*p2 = *p1; // value pointed by p2 = value pointed by p1
p1 = p2; // p1 = p2 (value of pointer is copied)
*p1 = 40; // value pointed by p1 = 20
cout << "X is " << X << endl;
cout << "Y is " << Y << endl;
return 0;
}

TASK

1. Explain in details what the program does? 

2. What is the output

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