Proof 2: 14 sin x dx tan xdx = /6 COs x 1 -= sec x dv = sin xdx cos x du = sec x tan xdx v =-cos x 14 14 | tan xdx = uv- | vdu 16 14 /4 1 -(-cosx)- [ (-cos x)sec x tan xdx cos x tan xdx = /6 14 tan xdx = -1+ tan xdx cos x cos x /6 /4 /4 tan xdx = -1+ tan xdx %3D /6 0 = -1

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