Propane (C₂H₂) is burned in a combustion chamber at a flow rate of 30.00 m³/min with 30.0% excess air. If the propane and air streams enter the chamber at 21.0 °C and 1.15 atm (absolute), and the products leave the chamber at 270.0°C and 3.20 atm (absolute), what is the volumetric flow rate of product gas from the chamber? Assume 100% conversion and ideal behavior. To solve for the flow rate, first label the process flow diagram. Label any quantities as "unknown" if they are not given or implied and "none" if the quantity is zero. Do not leave any blank spaces. Variable names are given for reference later.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Chapter1: Introduction
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Propane (C₂H₂) is burned in a combustion chamber at a flow rate of 30.00 m³/min with 30.0% excess air. If the propane and air
streams enter the chamber at 21.0 °C and 1.15 atm (absolute), and the products leave the chamber at 270.0°C and 3.20 atm
(absolute), what is the volumetric flow rate of product gas from the chamber? Assume 100% conversion and ideal behavior. To
solve for the flow rate, first label the process flow diagram. Label any quantities as "unknown" if they are not given or implied
and "none" if the quantity is zero. Do not leave any blank spaces. Variable names are given for reference later.
P₁-
n₁ =
V₁ =
T₂=
n₂ =
y₁ =
½/₂₁
₁ =
A₂ =
1.15
m²/min C,H,
°C
atm
My =
m³/min air
°C
atm
mol/min air
mol O/mol air
mol N₂/mol air
V₂ =
unknown
0.21
Combustion
chamber
30.00
Answer Hank
What is the molar flow rate of air into the combustion chamber?
3.20
none
What is the molar flow rate of products leaving the combustion chamber?
Use the ideal gas law to find the molar flow rate of propane into the combustion chamber.
n₂
n6=
n₂=
na
21.0
=
270.0
m³/min product
°C
atm
mol/min product
mol/min CO,
mol/min H₂O
mol/min 0₂
mol/min N₂
mol/min C,H,
0.79
Use the ideal gas law to find the volumetric flow rate of products leaving the combustion chamber.
mol C.H./min
mol air/min
mol products/min
Transcribed Image Text:Propane (C₂H₂) is burned in a combustion chamber at a flow rate of 30.00 m³/min with 30.0% excess air. If the propane and air streams enter the chamber at 21.0 °C and 1.15 atm (absolute), and the products leave the chamber at 270.0°C and 3.20 atm (absolute), what is the volumetric flow rate of product gas from the chamber? Assume 100% conversion and ideal behavior. To solve for the flow rate, first label the process flow diagram. Label any quantities as "unknown" if they are not given or implied and "none" if the quantity is zero. Do not leave any blank spaces. Variable names are given for reference later. P₁- n₁ = V₁ = T₂= n₂ = y₁ = ½/₂₁ ₁ = A₂ = 1.15 m²/min C,H, °C atm My = m³/min air °C atm mol/min air mol O/mol air mol N₂/mol air V₂ = unknown 0.21 Combustion chamber 30.00 Answer Hank What is the molar flow rate of air into the combustion chamber? 3.20 none What is the molar flow rate of products leaving the combustion chamber? Use the ideal gas law to find the molar flow rate of propane into the combustion chamber. n₂ n6= n₂= na 21.0 = 270.0 m³/min product °C atm mol/min product mol/min CO, mol/min H₂O mol/min 0₂ mol/min N₂ mol/min C,H, 0.79 Use the ideal gas law to find the volumetric flow rate of products leaving the combustion chamber. mol C.H./min mol air/min mol products/min
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