Prove the following statement by mathematical induction. 1 1 1 1 For every integer n2 1, 1-2 2-3 3-4 n(n + 1) n +1 Proof (by mathematical induction): Let P(n) be the equation 1 1 1 1 1-2 2-3 3- 4 n(n + 1) n+1 We will show that P(n) is true for every integer n2 1. Show that P(1) is true: Select P(1) from the choices below. 1 O P(1) 1-2 1 O P(1) 1 +1 1 1-2 1 1 1 1 1-2 2-3 3. 4 1-2 1 +1 1 1 1- 2 1(1 + 1) 1+1 The selected statement is true because both sides of the equation equal the same quantity. Show that for each integer k 2 1, if P(k) is true, then P(k + 1) is true: Let k be any integer with k 2 1, and suppose that P(k) is true. Select the expression for the left-hand side of P(k) from the choic 1 1 1- 2 k(k + 1) 1 1 1.2 2-3 3. 4 1 1 1 1-2 2-3 3. 4 k(k + 1) 1 1 1 2 -3 k(k + 1) 1-2 3.4 1 The right-hand side of P(k) is *(k +1) [The inductive hypothesis states that the two sides of P(k) are egual.]

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.5: Mathematical Induction
Problem 42E
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Prove the following statement by mathematical induction.
1
For every integer n 2 1,
1.2
1
1
1
2-3
3-4
n(n + 1)
n +1
Proof (by mathematical induction): Let P(n) be the equation
1
1
1
1
1.2
2-3
3-4
n(n + 1)
n+1
We will show that P(n) is true for every integer n2 1.
Show that P(1) is true: Select P(1) from the choices below.
1
O P(1)
1-2
1
O P(1)
1+1
1
1.2
1
1
1
1
1-2
2 -3
3. 4
1-2
1+ 1
1
1
%3D
1.2
1(1 + 1)
1+1
The selected statement is true because both sides of the equation equal the same quantity.
Show that for each integer k 2 1, if P(k) is true, then P(k + 1) is true:
Let k be any integer with k 2 1, and suppose that P(k) is true. Select the expression for the left-hand side of P(k) from the choices below.
1
1
1- 2
k(k + 1)
1
1
1
1- 2
2-3
3.4
1
1
1
1
1- 2
2-3
3. 4
k(k + 1)
1
1
1
1.2
2-3
3. 4
k(k + 1)
1
The right-hand side of P(k) is
*(k +1)
[The inductive hypothesis states that the two sides of P(k) are egual.]
Transcribed Image Text:Prove the following statement by mathematical induction. 1 For every integer n 2 1, 1.2 1 1 1 2-3 3-4 n(n + 1) n +1 Proof (by mathematical induction): Let P(n) be the equation 1 1 1 1 1.2 2-3 3-4 n(n + 1) n+1 We will show that P(n) is true for every integer n2 1. Show that P(1) is true: Select P(1) from the choices below. 1 O P(1) 1-2 1 O P(1) 1+1 1 1.2 1 1 1 1 1-2 2 -3 3. 4 1-2 1+ 1 1 1 %3D 1.2 1(1 + 1) 1+1 The selected statement is true because both sides of the equation equal the same quantity. Show that for each integer k 2 1, if P(k) is true, then P(k + 1) is true: Let k be any integer with k 2 1, and suppose that P(k) is true. Select the expression for the left-hand side of P(k) from the choices below. 1 1 1- 2 k(k + 1) 1 1 1 1- 2 2-3 3.4 1 1 1 1 1- 2 2-3 3. 4 k(k + 1) 1 1 1 1.2 2-3 3. 4 k(k + 1) 1 The right-hand side of P(k) is *(k +1) [The inductive hypothesis states that the two sides of P(k) are egual.]
[The inductive hypothesis states that the two sides of P(k) are equal.]
We must show that P(k + 1) is true. P(k + 1) is the equation
*+1
1
1
(&+1) +1
1.2
2-3
3- 4
*+1
k+1
Which of the following choices shows the result of applying the inductive hypothesis to the expression on the left-hand side of P(k + 1)?
k
1
k+1
(k + 1)(k + 2)
k
1
k +1
k(k + 1)
(k + 1)(k + 2)
1-2 K(k + 1)
(k + 1)(k + 2)
1
1
1
1
1.2
2-3
3. 4
k(k + 1)
(k + 1)(k + 2)
k +1
( +1) +1
When the left-hand and right-hand sides of P(k + 1) are simplified, they both can be shown to equal
. Hence P(k + 1) is true, which completes the inductive step.
[Thus both the basis and the inductive steps have been proved, and so the proof by mathematical induction is complete.]
Transcribed Image Text:[The inductive hypothesis states that the two sides of P(k) are equal.] We must show that P(k + 1) is true. P(k + 1) is the equation *+1 1 1 (&+1) +1 1.2 2-3 3- 4 *+1 k+1 Which of the following choices shows the result of applying the inductive hypothesis to the expression on the left-hand side of P(k + 1)? k 1 k+1 (k + 1)(k + 2) k 1 k +1 k(k + 1) (k + 1)(k + 2) 1-2 K(k + 1) (k + 1)(k + 2) 1 1 1 1 1.2 2-3 3. 4 k(k + 1) (k + 1)(k + 2) k +1 ( +1) +1 When the left-hand and right-hand sides of P(k + 1) are simplified, they both can be shown to equal . Hence P(k + 1) is true, which completes the inductive step. [Thus both the basis and the inductive steps have been proved, and so the proof by mathematical induction is complete.]
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