Prove the following statement by mathematical induction. 1 1 1 1 For every integer n2 1, 1-2 2-3 3-4 n(n + 1) n +1 Proof (by mathematical induction): Let P(n) be the equation 1 1 1 1 1-2 2-3 3- 4 n(n + 1) n+1 We will show that P(n) is true for every integer n2 1. Show that P(1) is true: Select P(1) from the choices below. 1 O P(1) 1-2 1 O P(1) 1 +1 1 1-2 1 1 1 1 1-2 2-3 3. 4 1-2 1 +1 1 1 1- 2 1(1 + 1) 1+1 The selected statement is true because both sides of the equation equal the same quantity. Show that for each integer k 2 1, if P(k) is true, then P(k + 1) is true: Let k be any integer with k 2 1, and suppose that P(k) is true. Select the expression for the left-hand side of P(k) from the choic 1 1 1- 2 k(k + 1) 1 1 1.2 2-3 3. 4 1 1 1 1-2 2-3 3. 4 k(k + 1) 1 1 1 2 -3 k(k + 1) 1-2 3.4 1 The right-hand side of P(k) is *(k +1) [The inductive hypothesis states that the two sides of P(k) are egual.]
Prove the following statement by mathematical induction. 1 1 1 1 For every integer n2 1, 1-2 2-3 3-4 n(n + 1) n +1 Proof (by mathematical induction): Let P(n) be the equation 1 1 1 1 1-2 2-3 3- 4 n(n + 1) n+1 We will show that P(n) is true for every integer n2 1. Show that P(1) is true: Select P(1) from the choices below. 1 O P(1) 1-2 1 O P(1) 1 +1 1 1-2 1 1 1 1 1-2 2-3 3. 4 1-2 1 +1 1 1 1- 2 1(1 + 1) 1+1 The selected statement is true because both sides of the equation equal the same quantity. Show that for each integer k 2 1, if P(k) is true, then P(k + 1) is true: Let k be any integer with k 2 1, and suppose that P(k) is true. Select the expression for the left-hand side of P(k) from the choic 1 1 1- 2 k(k + 1) 1 1 1.2 2-3 3. 4 1 1 1 1-2 2-3 3. 4 k(k + 1) 1 1 1 2 -3 k(k + 1) 1-2 3.4 1 The right-hand side of P(k) is *(k +1) [The inductive hypothesis states that the two sides of P(k) are egual.]
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.5: Mathematical Induction
Problem 42E
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