Prove the following statement. The difference of any two odd integers is even. Proof: Let m and n be any odd integers. By definition of odd, there are integersr and s so that m can be expressed in terms of r andn can be expressed in terms of s as follows. m = n = Write m - n in terms ofr and s and factor out a 2 to obtain m - n = Now is an integer because differences V of integers are integers. Therefore, m - n = 2: (an integer), and so m - n is even by definition of even Need Help? Read It Watch It

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.4: Prime Factors And Greatest Common Divisor
Problem 28E: Let and be positive integers. If and is the least common multiple of and , prove that . Note...
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Prove the following statement.
The difference of any two odd integers is even.
Proof: Let m and n be any odd integers. By definition of odd, there are integers r and s so that m can be expressed in terms of r andn can be expressed in terms of s as follows.
m =
n =
Write m - n in terms of r and s and factor out a 2 to obtain m - n =
Now
is an integer because differences V
of integers are integers.
Therefore, m – n = 2· (an integer), and so m – n is even
by definition of even
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Transcribed Image Text:Prove the following statement. The difference of any two odd integers is even. Proof: Let m and n be any odd integers. By definition of odd, there are integers r and s so that m can be expressed in terms of r andn can be expressed in terms of s as follows. m = n = Write m - n in terms of r and s and factor out a 2 to obtain m - n = Now is an integer because differences V of integers are integers. Therefore, m – n = 2· (an integer), and so m – n is even by definition of even Need Help? Watch It Read It
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