Provide opcodes for the following MOV instructions:.datamyByte BYTE ?myWord WORD ?.codemov ax,@datamov ds,ax ; a.mov ax,bx ; b.mov bl,al ; c.mov al,[si] ; d.mov myByte,al ; e.mov myWord,ax ; f.
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Provide opcodes for the following MOV instructions:
.data
myByte BYTE ?
myWord WORD ?
.code
mov ax,@data
mov ds,ax ; a.
mov ax,bx ; b.
mov bl,al ; c.
mov al,[si] ; d.
mov myByte,al ; e.
mov myWord,ax ; f.
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- Provide opcodes for the following MOV instructions:.datamyByte BYTE ?myWord WORD ?.codemov ax,@datamov ds,axmov es,ax ; a.mov dl,bl ; b.mov bl,[di] ; c.mov ax,[si+2] ; d.mov al,myByte ; e.mov dx,myWord ; f.(a) Find the value of AX and EAX registers.dataarrayW WORD 7000h,8000h,9000harrayD DWORD 1,2,3,4.codemov ax,[arrayW+2] ; AX =mov ax,[arrayW+4] ; AX =mov eax,[arrayD+4] ; EAX =(b) write a program that adds the following three bytes:.datamyBytes BYTE 80h,66h,0A5hCan you show me the screen shot of the output consoleof the following assembly code please INCLUDE Irvine32.inc .data multiplicand1 DWORD 65531 multiplier1 DWORD 1029 multiplicand2 DWORD 699050 multiplier2 DWORD 5461 multiplicand3 DWORD 21 multiplier3 DWORD 178956970 .codeBitwiseMultiply PROC xor edx, edx ; Clear edx mov ecx, eax ; Save multiplier in ecx mov eax, ebx ; Move multiplicand to eax mov ebx, 0 ; Clear ebxloop_start: test cl, 1 ; Check if the lowest bit of the multiplier is set jz shift_left ; If not, skip to shift_left add ebx, eax ; Add multiplicand to productshift_left: shl eax, 1 ; Shift multiplicand left by 1 bit rcl edx, 1 ; Rotate the carry flag into edx shr cl, 1 ; Shift the multiplier right by 1 bit jnz loop_start ; Loop until the multiplier is zero mov eax, ebx ; Move the result back to eax…
- Suppose that you are given the following program.Inside someProcedure, what numerical operand should be used with the RET instruction?.datax DWORD 153461y BYTE 37z BYTE 90.codemain PROCpush xpush ypush zcall someProcedurepop xinc EAXmov EBX, zxor EAX, EBXexitmain ENDPEND MAINA fragment of code is given to compare text in the field alpha with a text in the field beta: .data alpha db 12 dup(?) beta db ’abrakadabra’, 0 ; ::: .code ; ::: mov esi, 0 mov ecx, 12 ns: mov dl, alpha[esi] cmp dl, beta[esi] jne wrong ;=====MISSING==== loop ns ; ::: wrong: Choose missing instruction to insert in the code line marked by the comment “MISSING”.What will be the contents of BX after the following instructions execute?mov bx,5stcmov ax,60hadc bx,ax
- Write programs that will accomplish the desired tasks listed below, using as few lines of code as possible e) Divide the data in RAM location 3EH by the number 12H ; put the quotient in R4 and the remainderin R5.f) Divide the data in RAM location 15H by the data in RAM location 16H ; put the quotient inexternal RAM location 7CH and the remainder in in external RAM location 7DH.g) Double the number in register R2, and put the result in register R3 (high byte) and R4 (low byte).Use logic operations.h) OR the contents of ports 1 and 2 ; put the result in external RAM location 0100Hi) Set Port 0, bits 1, 3, 5 and 7 to one, set the rest to zero.j) Clear bit 3 of RAM location 22H without affecting any other bit.k) Invert the data on the port 0 pins and write the data to port 1.What will be the value of BX after the following instructions execute?mov bx,0649Bhor bx,3AhAssume the following register contents:$t0 = 0xAAAAAAAA, $t1 = 0x12345678For the register values shown above, what is the value of $t2 for the following sequence of instructions?a. sll $t2, $t0, 44add $t2, $t2, $t1
- Assume the two instructions below are executed.AND R4, R4, #0STR R4, R7, #-1Which one of the statements below is correct? Group of answer choices The execution sets the value at memory address with label H to x1233. The execution sets the value in R4 to x400F. The execution sets the value at memory address with label H to x1234. The execution sets the value at memory address with label H to 0. The execution sets the value at memory address with label B to x1233.Write a MIPS program (please show the whole code with comments)Given the following data definition statements, compute the addresses of arr2, arr3, str1, and str2, given that the address of arr1 is 0x10010000. Show your steps for a full mark. Select “Show Labels Window (symbol table)” from the Settings menu in MARS to check the values of your computed addresses. .data arr1: .word 5:20 arr2: .half 7, -2, 8, -6 arr3: .space 100 str1: .asciiz "This is a message" str2: .asciiz "Another important string"Design a Read Only Memory (ROM) to implement the following, A097803, polynomial A=3(2x2 +1), with input (x): 0≤(x)≤7 (a) What is the size of the initial (unsimplified) ROM ? (b) What is the size of the final (simplified) ROM ? (c) Show in detail the final ROM layout, using LogiSim.can you do letter C using Logisim APPthank you!