Provide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3= 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports.A v3V37(m) oThe singularity functions areq = R1(x)ª – v1( – P)ª – v2(x – Q)ª + R2(x – R)ª- 2-V = R1 – v1(x – D)B – v2(x – E)B + R2(x – F)®(1)M = R1x – v1(x – G)° – v2(x – H)° + R2(x –(2)From the given singularity functions, the exponents areA =B =C=The distances areP=mmQ =mmR=mmD=mmE=mmF=mmG=mmH=mmmmReactions force R =kN and reaction force R2 =kN

Answered: Image /qna-images/answer/ba5d97ff-fc45-4725-a390-1d7047cc351c.jpg

Provide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. AA va (mem) o The singularity functions are q = R1(x)ª – v1(x – P)4 – v2(x – Q)ª + R2(x – R)ª :-. :-. V = R1 – v1(x – D)“ – v2(x – E)* + R2(x – F)“ (1) M = R1x – v1(x - G)° – v2(x – H)C + R2(x – I)° (2) From the given singularity functions, the exponents are A = B= C= The distances P= mm Q = mm R= mm D= mm E= mm F= mm G= mm H= mm mm Reactions force R = |kN and reaction force R2 = |kN

Provide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. AA va (mem) o The singularity functions are q = R1(x)ª – v1(x – P)4 – v2(x – Q)ª + R2(x – R)ª :-. :-. V = R1 – v1(x – D)“ – v2(x – E)* + R2(x – F)“ (1) M = R1x – v1(x - G)° – v2(x – H)C + R2(x – I)° (2) From the given singularity functions, the exponents are A = B= C= The distances P= mm Q = mm R= mm D= mm E= mm F= mm G= mm H= mm mm Reactions force R = |kN and reaction force R2 = |kN

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.5.10P: Solve the preceding problem (W 250 × 44.8) if the resultant force P equals 110 kN and E = 200 GPa.

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