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- Compound X is insoluble in cold KMnO4, Br2 in CCl4, and conc. H2SO4. Compound X is most likely: a. an alkane b. none of these c. an alkene d. an alcohol e. an alkyl halide Indicate which of the ff. statements regarding nucleophilicity is incorrect. F- is more nucleophilic, hence, more reactive towards methyl iodide than Cl-. Second row elements are more nucleophilic than first row elements of comparable basicity. The rate of SN2 reaction may be markedly affected by the nucleophilicity of the attacking atom. Nucleophilicity is the affinity of a nucleophile to an electrophilic carbon Which of the following alkynes can be deprotonated by NaNH2 in liquid NH3? 3-Methylhex-2-yne Pent-2-yne 3-Methylbutyne none of these Hex-3-yneOChem help with IUPAC names involving Ph and Bn The phenyl group (Ph-R, C6H5-R) can be formed by removing a hydrogen from benzene and attaching a substituent to where the hydrogen was removed. The benzyl group (abbv. Bn), similar to the phenyl group, is formed by manipulating the benzene ring. In the case of the benzyl group, it is formed by taking the phenyl group and adding a CH2 group to where the hydrogen was removed. Its molecular fragment can be written as C6H5CH2-R, PhCH2-R, or Bn-R. Please provide the IUPAC name for the following: (Ph)2CHC(CH3)2CC(CH2)3CH(Bn)CHOThe SN2 reaction of (S)-2-brombutan with cyanide (-CN) with the others from the server.
- Match the unknowns with their correct class of organic compounds based on the given qualitative tests below. Unkown A Unkown B Unkown C Unkown D Choices: I. Ester II. Amide III. Acid anhydride IV. Acid halidea. For this acid-base reaction: C⊖H3 + H3O+ −−→ CH4 + H2O, the conjugate acid of carboanion (C⊖H3) is _________________ b. Complete the equation: HC≡N + NaOH −−→ ___________+__________ c. Rank the acidity of these: NH3, HF, H2O, HCl, NaH Most acidic______>_______>_______>_______>_______least acidic d. The Ka of acetic acid (found in vinega) is 1.8×10-5. Then the pKa of formic acid isChecking my answer, there was difference with solution. (organic chemistry smith 5th ed 2.47P (d)) Solution said 'the acid base reaction between pentyne and ammonia is product way because pka of pentyne is 25, ammonia is 38 so pentyne will be deprotanted by ammonia.' but I think (and as written in the book) NH4+ is stronger acid than pentyne and acid-base reaction works when reactant is stronger acid than product conjugate acid. It isn't match that pentyne makes NH4+. who is incorrect?
- Explain and show step by step how did the answer or IUPAC name derived in letter b,f,h,k and L. This is about carboxylic acids and its derivatives.Please help with 4B 4C 4D and if possible please with 4E as well. I am very confused and if all 4 parts can be answered I would very much appreciate it! Thank you in advance 4E) Formic acid (HCO2H) and piperidine (C5H11N)KMnO4, warm, conc'd reacts with hept-1-ene to yield __________. CO2, hex-1-ene CO2, hexanoic acid Formic acid, pentanoic acid Ethanoic acid, pentanal Formic acid, hexanone
- Complete synthesis, include reagents and intermediate compounds. If functional group needs to be protected, show.When aspirin is made from acetic acid, the by product is H2O; when acetic anhydride 1Sused, the by-product is acetic acid. When acetyl chloride is used (see above), the by product is HC1. Which route should you use if you were working for Leica, a company that mass produces aspirin on a daily basis? Why?Explain and show step by step how did the answer or IUPAC name derived in letter b,f,h,k, and L. Please answer it all. This is about Carboxylic acid and its derivative.