PS- UCM Horizontal m1 = 0.25 kg O m2 = 0.75 kg Mass 1 and mass 2 are connected to the opposite ends of a string of negligible mass that passes through a frictionless tube (as shown). Due to gravity, m2 pulls the string down ward thereby pulling m1 closer to the tube. This unbalance force within the system can be equalized by spinning m1 horizontally by way of holding the tube to generate centripetal force which will create equilibrium. At what linear velocity should m1 be spun to create equilibrium? What is the tension on the string when there is equilibrium? L = 0.80 m

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Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.