public class CAT_ONE { public static int solve(int n) { if (n <= 1) return n; return solve(n-1) + solve(n-2); public static void main(String[] args) { int n = 90; for (int i = 0; i < n; i++){ System.out.print(solve(i) +" ");
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While using a different technique, re-right the
![public class CAT_ONE {
public static int solve(int n) {
if (n <= 1)
return n;
return solve(n-1) + solve(n-2);
public static void main(String[] args) {
int n = 90;
for (int i = 0; i < n; i++){
System.out.print(solve(i) +" ");
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b47d31c-8208-41d5-8a49-c9a5946ea5fe%2F9f56ef59-6f33-499f-9464-6535685d7ab6%2Fkajvboi_processed.png&w=3840&q=75)
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- Combinations refer to the combination of n things taken p at a time withoutrepetition. A recursive definition of C(n, p) is C(n, 0) = C(n, n) = 1, otherwiseC(n, p) = C(n - 1, p) + C(n - 1, p - 1).Write a method public static long C(long n, long p) that computesand returns C(n, p).Answer the given question with a proper explanation and step-by-step solution. public class mathFormula { // Iterative implementation public static int iterative(int n) { if (n == 0) return 1; if (n == 1) return 2; int f1 = 1, f2 = 2, fn = 0; for (int i = 2; i <= Math.abs(n); i++) { fn = f1 - f2; f1 = f2; f2 = fn; } return (n < 0 && n % 2 == 0) ? -fn : fn; } // Recursive implementation public static int recursive(int n) { if (n == 0) return 1; if (n == 1) return 2; if (n > 1) return recursive(n - 1) - recursive(n - 2); return -recursive(-n); } // Memoization implementation public static int memoization(int n) { int[] memo = new int[Math.abs(n) + 1]; memo[0] = 1; memo[1] = 2; return memoizationHelper(n, memo); } public static int memoizationHelper(int n, int[] memo) { if (memo[Math.abs(n)] != 0) return (n < 0 && n % 2 == 0) ? -memo[Math.abs(n)] : memo[Math.abs(n)]; memo[Math.abs(n)] = memoizationHelper(n - 1, memo) - memoizationHelper(n - 2, memo); return (n…Java Palindrome Detector A palindrome is any word, phrase, or sentence that reads the same forward and backward. Here are some well-known palindromes: Able was I ere I saw Elba A man a plan a canal Panama Desserts I stressed Kayak Write a boolean method that uses recursion to determine whether a String argument is a palindrome. The method should return true if the argument reads the same forward and backward. Demonstrate the method in a program.
- JAVA A Matryoshka, or Russian nesting doll is either solid or hollow. If it is hollow, it contains another doll (which can also be hollow or solid). Given the supplied Doll class, implement a recursive method named show that returns a String representing the chain for dolls, for example Natasha contains Tanya contains Peter public class Doll{ private String name; private Doll dollInside; /** * Constructs a hollow doll with the doll it contains. */ public Doll(String theName, Doll theDoll) { name = theName; dollInside = theDoll; } /** * Constucts a solid doll. */ public Doll(String theName) { name = theName; dollInside = null; } public boolean isSolid() { return dollInside == null; } public String getName() { return name; } public Doll getDollInside() { return dollInside; }} public class DollViewer{ public static String show(Doll d) { /* code goes here */ } public static void main (String [] args) { Doll dolls1 =…Write a recursive method called digitCount() that takes two integers, n and m as a parameter and returns the number of digits in n that are equal to m. Assume that n≥0 and 0≤m≤9 Ex: If the input is: 34443215 4 3 import java.util.Scanner; public class LabProgram { /* TODO: Write recursive digitCount() method here. */ public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int digits; int n= scnr.nextInt(); int m= scnr.nextInt(); digits = digitCount(n, m); System.out.println(digits); }}JAva Implement a class Robot that simulates a robot wandering on an infinite plane. The robot is locatedat a point with integer coordinates and faces north, south, east, or west. Supply methods:public void turnLeft()public void turnRight()public void move()public Point getLocation()public String getDirection()The turnLeft and turnRight methods change the direction but not the location. The move method movesthe robot by one unit in the direction it is facing. The getDirection method returns a string “N”, “S”,“E”, “W”. For the new object, the initial location and facing should be specified. For the initial facing, 0means north, 1 means east, 2 means south, and 3 means west.A tester class, RobotTester, has been provided as follows to help you how to implement the Robot class.Therefore, implement the Robot class such that the following RobotTester class can be executed withoutany changes.import java.awt.Point;/**A class to test the Robot class.*/public class RobotTester{/**Tests the…
- In Java trace the table for a while loop public class Main { public static void main(String[] args) { // Question 2 j = 30; x=5; for (int i=1;i<=2;i++) { while (j > 20) { j=j-x*i; ++x; }// end of while }// end of for j x i j<=2 j>20Methods in Java Write a program that accepts three strings: first name, last name, age, and nationality. Create an object of the class Person and assign the inputs to their respective attributes. In the class, create a method greeting() that prints the attributes. Inputs 1. Input Cody Chum 20 Filipino Sample Output Enter first name: Cody Enter last name: Chum Enter age: 20 Enter nationality: Filipino Hello, I am Cody Chum, 20 years old and a Filipino!Write a recursive Java method that takes a String as a parameter and returns true if the String is a palindrome. You may assume that the string only contains lower case characters (i.e. no numbers, spaces, punctuation, etc).
- The intName method in the "Problem Solving: Stepwise Refinement" section accepted arguments < 1,000. Using a recursive call, extend its range to 999,999. For example an input of 12,345 should return " twelve thousand three hundred forty five". Note that some number names may have extra spaces at the beginning or end. import java.util.Scanner; public class IntegerName { /** Turns a number into its English name. @param number a positive integer < 999,999 @return the name of the number (e.g. "two hundred seventy four") */ public static String intName(int number) { int part = number; // The part that still needs to be converted String name = ""; // The name of the number if (part >= 1000) { // Recursively call intName } if (part >= 100) { name = digitName(part / 100) + " hundred"; part = part % 100; } if (part >= 20) { name = name + " " + tensName(part); part = part % 10; } else if (part >= 10) { name = name + " " + teenName(part); part = 0; } if (part > 0) { name =…JAVA Write a static recursive method evenFactors that takes as input two positive integers and prints the even factors of the first integer that are greater than or equal to the second integer. For example, evenFactors(18,1) prints 2, 6, and 18, since the even factors of 18 that are greater than or equal to 1 are 2,6, and 18.import java.util.Scanner; public class LabProgram { // Recursive method to draw the triangle public static void drawTriangle(int baseLength, int currentLength) { if (currentLength <= 0) { return; // Base case: stop when currentLength is 0 or negative } // Calculate the number of spaces needed for formatting int spaces = (baseLength - currentLength) / 2; if (currentLength == baseLength) { // If it's the first line, don't output spaces before the first '*' System.out.println(" ".repeat(spaces) + "*".repeat(currentLength)); } else { // Output spaces and asterisks System.out.println(" ".repeat(spaces) + "*".repeat(currentLength)); } // Recursively call drawTriangle with the reduced currentLength drawTriangle(baseLength, currentLength - 2); } public static void drawTriangle(int baseLength) { drawTriangle(baseLength, baseLength); } public…