Q.26: For the circuit shown Find: 1. Turn ratio "n" for max. power delivered to (20KQ) resistor. 2. Maxi. power delivered to the load. (Ans.: n=50 & Pm=4.5W)
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- in the circuit given in the figure , VDD = 20 V ,Rs= 1 kohm , VGSQ= -2.6 v, IDQ = 2.6 mA.the transistor specifically has values of IDSS = 8mA , Vp= -6 V , and gos =25 µS. what should be the RD resistance for the output voltage to be -24.85 mV when an AC voltage of 12 mV is applied to the transistor input ? Options: a) 3.3 kohm b) 4.2 kohm c) 4.5 kohm d) 3.6 kohm e) 3.9 kohmamplifier (boost) DC-DA converter circuit, given below; 1- Source voltage (E) value: In the voltage range of [A B] (Volts) 2- Switching frequency (f) value: M kHz 3- Voltage between load terminals (Vload) F (volt) 4- Capacity value is 470 (microF) 5- Pload>= H(watts) consumed per load In which case below do you see the lowest L inductance value in microH that can keep the DC-DC converter in a continuous current state under the conditions? A=25 VOLT B=40 VOLT M= 25kHz F = 55 VOLT H=15 Watts a) 454.5475 b) 382,045 c) 263.62 d) 128.5 e) 581.81FOLLOW UP QUESTIONS: BIPOLAR JUNCTION TRANSISTOR (BJT) SOLVE FOR: a.) VCE (off) CONSTRUCT A DC LINE SHOWING THE VALUES OF b.) IC (sat) c.) VCE (off) d.) ICQ e.) VCEQ
- Consider the following circuit. Calculate the output voltage when VGS=0 and VGS=-10V. Also, calculate the on-off ratio.It is desired to have a maximum power transfer from an amplifier to the load of the system. The resistance in the amplifier and the voltage are 120 Ohms 160 volts respectively. Twice the turns of the wires on the conductor at the secondary side of the transformer and the turns of the wire at the primary side of the transformer is 35. The impedance at the load is 53.33 ohms. If the difference of the turns of the wire at the primary side of the transformer and primary side of the transformer is 5. Answer the following questions below: i. What is the maximum power transfer from the generator to the load ii. Show that the transformer assisted in transferring maximum power from the generator to the load. iii. What is the power transfer from the generator to the load when there is no transformer between the amplifier and the loadIn the Boost DA-DA circuit:Source voltage (E) value: in the range of [17-29] (volts),Switching frequency (f) value: 20 khz,Voltage between load ends: 40VCapacitance value: 470uFPower dissipated at load: 10 watts What is the lowest inductance L, in uH, that can keep the DC-DC converter in continuous current under these conditions? a) 269.3731 b) 415.4375 c) 364.8204 d) 163.6472 e) 578.1875
- In the circuit given above VS = 20,0V, R1 = 7kΩ, R2 = 7kΩ, If RL = 17,0kΩ and Vzener = 6,4, how many mW will Pzener be?Hi! I need answer for questions below: Principles of operation of darlington pair DC analysis of darlington pair equation/formulas. (Applying KVL, current gain, voltage gaing etc.) AC analysis of darlington pair equation/formulas. (Applying KVL, current gain, voltage gaing etc.)Power Electronics. In the Buck-Boost DC-DC converter circuit:Welding voltage [40-80]VSwitching frequency (f) 25khzVoltage between load terminals 55VCapacitance value 470uFLoad current value [10-25]A Under these conditions, which is the lowest ripple (delta IL) amount of the current passing through the coil (L) in Amps for the lowest L inductance value that can keep the DC-DC converter in a continuous current state? A) 23.9803B) 118.75C) 84.3750D) 47.5E) 59.9507F) 33.75
- If an amplifier’s impedance (AC Resistance) is 8 ohms, why should a speaker of 8 ohms be chosen to deliver the sound? What happens if a speaker of 4 ohms is employed instead? How about a higher impedance of 16 ohms?In the circuit above, if V1 = + 28V, R = 17,612, RL = 14,3 and the zener voltage is 8,0, what is the peak point of the voltage falling on the resistor R in the negative alternans of V1?Explain, in your own words with the aid of the graph the Load Line Analysis concept. The student should illustrate the following points on the graph: ICsat VCEcutoff Different IBQ values Load Line Q-Point