Q1) A drain 60m long is to be excavated at a gradient of (1 in 30) from the station0+00 were the design level (formation level) is 126.15 m./Natural ground elevationsare taken at 50m) Intervals along the centerline as below:Stationnatural ground elevation0+00127.63-26.150+40128.420+80129.35217° 19°381+20129.351+60128.7bo= 4m/n=1 in cut n = 2 in fill, S-20 assume left side is higher than right side.Calculate the volume of cut and volume of fill by using end area method for volumedetermination.O45330100

Solution: Given: Design level = 126.15 m Station Natural Ground elevation 0+00 127.63 0+40…

Q1) A 0+00 were the design level (formation level) is 126.15 m./Natural ground elevations are taken at 50m) Intervals along the centerline as below: Station natural ground elevation -26-15 127.63 128.42 129.35 217° 19° 38 129.35 128.7 bo=4m/n=1 in cut n = 2 in fill, S=20 assume left side is higher than right side. Calculate the volume of cut and volume of fill by using end area method for volume determination. O 0+00 0+40 0+80 1+20 1+60 4

Q1) A 0+00 were the design level (formation level) is 126.15 m./Natural ground elevations are taken at 50m) Intervals along the centerline as below: Station natural ground elevation -26-15 127.63 128.42 129.35 217° 19° 38 129.35 128.7 bo=4m/n=1 in cut n = 2 in fill, S=20 assume left side is higher than right side. Calculate the volume of cut and volume of fill by using end area method for volume determination. O 0+00 0+40 0+80 1+20 1+60 4

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

1) A concrete lined irrigation channel with Manning’s n = 0.020 is needed to convey 12.5 m3/s of water. The channel has a trapezoidal section with bottom slope So = 0.0015. Determine the effective size of the channel if the side slope is restricted to 3 (horizontal) : 1 (vertical).
Water flows through a gravel (very rough), earth excavated, triangular channel at arate of 150L/s. See flow area schematic below. The angle of the sides with the horizontal is 20°.Determine the normal depth in the channel, y n, using Manning’s formula if the channel resides on a 0.001ground slope.
water flows at 12m^/s in a concrete trapezoidal channel n=0.015 bottom width 4m side slopes 2H:1V longitudinal slope = 0.0009.if the depth flow at a gauging station is measured as 0.8m use the direct step method to find the location where the depth is 1.0m
From station (A) 5 + 120 with center height of 1.8 m in fill, the ground lines makes a uniform slope of 5% to station(B) 5 + 220 whose center height is 4.25 m in cut . Find the distance where the excavation be extended from station (B) 5 + 220.
An open channel having a slope of 0.0065 is used to carry 1 cubic meter per second of water. 1. Find the depth of for a most efficient triangular section. n=0.013 2. Compute the depth if it is a trapezoidal channel whose depth is half the base with side lop of 2 horizontal to 1 vertical. 3. For a trapezoidal channel whose depth is half the base and side slopes at 62 degrees with the horizontal, find the depth for minimum seepage
Water flows in a triangular V-notch steel channel, with vertex angle of 75 degrees, at a velocity of 1.2 m/s. find the normal depth of flow if the channel is laid on a slope of 0.0017. Use n=0.014
Find the required slope of a rectangular open channel when the water flows at a rate of 20,000 L/s, having a base width of 4m and depth water depth of 2.5m. (n = 0.013)
A trapezoidal irrigation canal with side slope of 1.5 H to V is proposed to be lined with bricks to reduce seepage losses. It is required too carry a discharge of 20m ^ 2 / s of water. Find the wetted perimeter for minimum amount of lining and required bed slope. The value of Manning's Nis given as 0.015 and it is stipulated that average velocity cannot exceed 1 m/s.
Water is flowing at a rate of 4.5m3/s in a trapezoidal channel whose bottom width is 2.4m and side slopes are 1 vertical to 2 horizontal. Compute for the channel depth if n = 0.012 and So = 0.0001
The table below is the page of a level field book. 1) Calculate the difference in level between point A and G. 2) If it is required to build a horizontal embankment along the line AG, so that the elevation of the embankment is higher than the original ground surface with 150cm at point A. Calculate the depth of fill at point D. let RL of A=30m (all the readings in meter)
At what depth will water flow at 0.25m3/s in a 1.0m diameter concrete pipe (n=0.012) on a slope of 0.0004?
Q5. A 1 km long trapezoidal, concrete-lined (n = 0.013) channel is required to conveywater at 10 m3/sec. The channel bottom slope So is 0.001, and the side slope is1V:2H.a. Using the best hydraulic section approach, design the channel dimensions(water depth; channel depth, channel bottom width, etc.). Calculate the flowvelocity. Use the free-board at about 0.3 m. Sketch the section of your channelshowing all dimensions including top width.b. If the cost of excavations is $20 per cubic meter, how much is the excavationcost for the 1 km channel.c. If the lining cost (concert lined) is $200 per square meter, how much is thelining cost of the channel.