Q1 The following is the equation of flow over a rectangular weir. q = 0.415 (L-0.2 h) h¹.5 √√2g Where, q=volumetric flow rate, ft³/s L = crest height, ft h = weir head, ft g = acceleration of gravity, ft/s² a) Explain in details that the equation is dimensionally consistent. b) Calculate the volumetric flow rate in m³/min if the crest height is 2.45 m and weir head is 1 yd. c) Drive and equation with q in m³/m, L in m and h in yd. d) Repeat part (b) using the derived equation in part (c)

Elements Of Electromagnetics
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Solve b,c,d part please fast.
Q1 The following is the equation of flow over a rectangular weir.
q=0.415 (L-0.2 h) h¹.5√√2g
Where,
q= volumetric flow rate, ft³/s
L = crest height, ft
h = weir head, ft
g= acceleration of gravity, ft/s²
a) Explain in details that the equation is dimensionally consistent.
b) Calculate the volumetric flow rate in m³/min if the crest height is 2.45 m and
weir head is 1 yd.
c) Drive and equation with q in m³/m, L in m and h in yd.
d) Repeat part (b) using the derived equation in part (c)
Transcribed Image Text:Q1 The following is the equation of flow over a rectangular weir. q=0.415 (L-0.2 h) h¹.5√√2g Where, q= volumetric flow rate, ft³/s L = crest height, ft h = weir head, ft g= acceleration of gravity, ft/s² a) Explain in details that the equation is dimensionally consistent. b) Calculate the volumetric flow rate in m³/min if the crest height is 2.45 m and weir head is 1 yd. c) Drive and equation with q in m³/m, L in m and h in yd. d) Repeat part (b) using the derived equation in part (c)
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