Q#1: Write the Class for Circle. Read the following code and create the attributes, method, constructors of class according so that it produces the result as given below. Code: public class Main { public static void main(String[] args) { System.out.println("Value of PI: "+ Circle.PI); System.out.println("Square of 2.0 is: " + Circle.square(2.0)); Circle c1 = new Circle(3.4); Circle c2 = new Circle(2.9); c1.display(); c2.display(); System.out.println(c1.compare(c2)); System.out.println(c2.compare(c1)); c1 = c2.getCopy(); System.out.println(c1.compare(c2)); System.out.println(c2.compare(c1)); c1.set(5.0); System.out.println(c1.getRadius()); System.out.println(c1.getDiameter()); System.out.println(c1.getCircumference()); System.out.println(c1.getArea()); Circle c3 = c2.getClone(); c3.set(c1.getDiameter()); c2.display(); c3.set(c1); c1.display(); c2.display(); c3.display(); } } Output: Value of PI: 3.14 Square of 2.0 is: 4.0 Radius: 3.4, Diameter: 6.8, Circumference: 21.352, Area: 36.2984 Radius: 2.9, Diameter: 5.8, Circumference: 18.212, Area: 26.407400000000003 1 -1 0 0 5.0 10.0 31.400000000000002 78.5 Radius: 10.0, Diameter: 20.0, Circumference: 62.800000000000004, Area: 314.0 Radius: 5.0, Diameter: 10.0, Circumference: 31.400000000000002, Area: 78.5 Radius: 5.0, Diameter: 10.0, Circumference: 31.400000000000002, Area: 78.5 Radius: 5.0, Diameter: 10.0, Circumference: 31.400000000000002, Area: 78.5

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Note: This is a Java program question.

Q#1: Write the Class for Circle. Read the following code and create the attributes, method, constructors of class according so that it produces the result as given below.
Code:
public class Main {
public static void main(String[] args) {

System.out.println("Value of PI: "+ Circle.PI);

System.out.println("Square of 2.0 is: " + Circle.square(2.0));

Circle c1 = new Circle(3.4);

Circle c2 = new Circle(2.9);

c1.display();

c2.display();

System.out.println(c1.compare(c2));

System.out.println(c2.compare(c1));

c1 = c2.getCopy();

System.out.println(c1.compare(c2));

System.out.println(c2.compare(c1)); c1.set(5.0); System.out.println(c1.getRadius());

System.out.println(c1.getDiameter()); System.out.println(c1.getCircumference());

System.out.println(c1.getArea());

Circle c3 = c2.getClone();

c3.set(c1.getDiameter());

c2.display();

c3.set(c1);

c1.display();

c2.display();

c3.display();

}

}
Output:
Value of PI: 3.14

Square of 2.0 is: 4.0

Radius: 3.4, Diameter: 6.8, Circumference: 21.352, Area: 36.2984

Radius: 2.9, Diameter: 5.8, Circumference: 18.212, Area: 26.407400000000003

-1

5.0

10.0

31.400000000000002

78.5

Radius: 10.0, Diameter: 20.0, Circumference: 62.800000000000004, Area: 314.0

Radius: 5.0, Diameter: 10.0, Circumference: 31.400000000000002, Area: 78.5 Radius: 5.0, Diameter: 10.0, Circumference: 31.400000000000002, Area: 78.5 Radius: 5.0, Diameter: 10.0, Circumference: 31.400000000000002, Area: 78.5

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