Q2: A 20 KVA,8000/277 V, distribution transformer has the following resistances and reactance's R₂-320, R,-0.0502, X,-45 92, X-0.060, Re-250k2, Xm-30K The excitation branch impedances are given referred to the high voltage side of the transformer. (1) calculate and drawing the parameters of equivalent circuit of this transformer. (2) Assume that this transformer is supplying rated load at 277 V and 0.8 lagging power factor. what is the transformer Input voltage and calculate the Voltage Regulation and transformer Efficiency at this case?

Q2: A 20 KVA,8000/277 V, distribution transformer has the following resistances and reactance's R₂-320, R,-0.0502, X,-45 92, X-0.060, Re-250k2, Xm-30K The excitation branch impedances are given referred to the high voltage side of the transformer. (1) calculate and drawing the parameters of equivalent circuit of this transformer. (2) Assume that this transformer is supplying rated load at 277 V and 0.8 lagging power factor. what is the transformer Input voltage and calculate the Voltage Regulation and transformer Efficiency at this case?

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.57P: A two-winding single-phase transformer rated 60kVA,240/1200V,60Hz, has an efficiency of 0.96 when...

See similar textbooks

Similar questions

A two-winding single-phase transformer rated 60kVA,240/1200V,60Hz, has an efficiency of 0.96 when operated at rated load, 0.8 power factor lagging. This transformer is to be utilized as a 1440/1200-V step-down autotransformer in a power distribution system. (a) Find the permissible kVA rating of the autotransformer if the winding currents and voltages are not to exceed the ratings as a two-winding transformer. Assume an ideal transformer. (b) Determine the efficiency of the autotransformer with the kVA loading of part (a) and 0.8 power factor leading.
Consider Figure 3.25 of the text for a transformer with off-nominal turns ratio. (i) The per-unit equivalent circuit shown in part (c) contains an ideal transformer which cannot be accommodated by some computer programs. (a) True (b) False (ii) In the - circuit representation for real c in part (d), the admittance parameters Y11 and Y12 would be unequal. (a) True (b) False (iii) For complex c, can the admittance parameters be synthesized with a passive RLC circuit? (a) Yes (b) No
The transformer of Problem 3.16 is supplying a rated load of 50 kVA at a rated secondary voltage of 240 V and at 0.8 posr factor lagging. Neglect the transformer exciting current. (a) Determine the input terminal voltage of the transformer on the high-voltage side. (b) Sketch the corresponding phasor diagram. (c) If the transformer is used as a step-down transformer at the load end of a feeder whose impedance is 0.5+j2.0, find the voltage VS and the power factor at the sending end of the feeder.
Primary side-reduced equivalent circuit parameters of a 25 KVA, 50 Hz, 4000/400 Volt transformer R1 = 32 Ω, X1 = 45 Ω, Rc = 250000 Ω, R2 '= 66.14 Ω, X2' = 79.34 Ω, Xm It is given as = 30000 Ω. Since the secondary of the transformer is fed at a full load rated voltage with an advanced power factor of 0.9, for these operating conditions; a) Calculate the primary voltage using the T equivalent circuit. (Only the amplitude of the voltage and the phase value will not be entered.) b) Calculate the efficiency of the transformer. c )Calculate the voltage regulation of the transformer.
On the plate of the one-phase transformer, it is written 20kVA, 2000/200 V, 50 Hz. In the short-circuit test performed on the transformer, the results stated at the end of the problem were obtained. Draw the equivalent circuit of the short-circuit test with the low-voltage side of the transformer short-circuited, by overwriting the circuit element values. open circuit test high voltage side open circuit V= 200 A = 6a W = 200W closed circuit experiment low voltage side short circuit V= 200v A = 10 A W= 400W
1. A 30KVA, 6000/230V, 50Hz single phase transformer has HV and LV winding resistances of 10.2Ω and0.0016Ω respectively. The equivalent leakage reactance as referred to HV side is 34Ω. Find the voltageto be applied to the HV side in order to circulate the full load current with LV side short circuited. Alsoestimate the full load %regulation of the transformer at 0.8 lagging power factor.
SUBJECT: Electrical Apparatus INSTRUCTIONS: • Please write clearly and understable way. • Write all the corresponding Given before solving. • Draw/Illustrate the diagram/circuit or drawings that is related to the problem, HIGHLY REQUIRED. • Solve in step-by-step, no shortcut, with formulas before sulutions together with the units • Underline twice the Final Answer. PROBLEM: • A 2,000-KVA transformer (A) is connected in parallel with a 4,000-KVA transformer (B) to supply a 3-phase load of 5,000 KVA at 0.8 p.f. lagging. Determine the KVA supplied by each transformer assuming equal no-load voltages. The percentage volt drops in the windings at the rated loads are as follows: Transformer A: resistance 2%; reactance 8% Transformer B: resistance 1.6%; reactance 3%
Solve the following problems with complete solutions and unitsusing two(2) decimal digits. Use your own analysis andcomputations. 2. A 3-phase transformer, ratio 33/6.6-kV, Δ-Y, 2-MVA has a primary resistance of 8 Ω per phase and a secondary resistance of 0.08 Ω per phase. The percentage impedance is 7%. Calculate the secondary voltage with rated primary voltage and hence the regulation for full-load 0.75 power factor lagging conditions.
5) A short circuit test on 15kVa, 2400/240V, 60Hz transformer yields the following results: 6.25A, 132V and 215W. (A) determine the equivalent resistance referred to the high side in ohms, (b) determine the equivalent reactance referred to the high side in ohms,(c) determine the equivalent impedance referred to the high side in ohms, (d) determine the percent impedance of the transformer. Subject Electrical Apparatus and Devices
A 500kVA transformer has an open circuit test of 600W and the full load short circuit test of 700W, if the power factor of the transformer is 0.8 lagging, calculate theefficiency of the transformer and maximum efficiency transformer
The parameters of a 1000/250V, 50HZ single phase transformer are: R1=1.3 N, X1=2.8 N, R2=0.11 N, X2=0.2 N, R,=250 N, X,=900 N. If the load voltage is 220V, load power is 10kW, and load power factor is 0.8 lagging. Find by using the exact equivalent circuit: (i) Input current, (ii) The input voltage and power factor, (iii) The magnetizing current, (iv) The copper losses, (v) The voltage regulation.
SUBJECT: Elements of Electrical Machines DesignINSTRUCTIONS: - Please write clearly and understandable way. - Write all the corresponding Given with their corresponding symbols and units. - Draw/Illustrate the diagram/circuit or drawings that is related to the problem, IF POSSIBLE, which is HIGHLY REQUIRED. - Solve in step-by-step, no shortcut - Underline twice the Final Answer.PROBLEM: A 13800 / 480 V, 3-phase transformer bank is connected as a wye-delta configuration. What must be the turns ratio of each transformer?