A:1E IO ZV6 11,1K/s ª,l| zain IQالكهربائية المحاضرة 1. . .Solution / E at point P is equal to E, +E,E = E+E.E, = E1s +EE, = E1y +E2y5Dr. MuntherElectricityThe University of MisanCollege of ScienceFirst yearDr. MuntherE, = k,cos 0 + k,a +cos 0 = 2kcos eE, = ka + ysin 0 - k.asin 8 =0cos A =42agE, = 2k,(a² + y*)/ZQ2/ A dipole with charges -q and +q, and separation 2a, is located on the X-axis with itsmidpoint at the origin. A point charge Pis on the X-axis a distance r from the midpoint of thedipole, what is the electric field on P due to the dipole?inther

Answered: Image /qna-images/answer/0455e1a6-141a-4dcc-9904-0b7ef449f7aa.jpg

Q2/ A dipole with charges -q and +q, and neparation 2a, is located on the X-uxis with its midpoint at the origin. A point charge P is on the X-axis a distance r from the midpoint of the dipole, what is the electric field on P due to the dipole?

Q2/ A dipole with charges -q and +q, and neparation 2a, is located on the X-uxis with its midpoint at the origin. A point charge P is on the X-axis a distance r from the midpoint of the dipole, what is the electric field on P due to the dipole?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Electric field

A physical field present around an electrically charged particle that exerts a force on all other charged particles is called an electric field. The charged particles present in the field either repel or attract. From electric charges or time-varying magnetic fields, the electric field originates. One of the manifestations of electromagnetic force which is one of the four fundamental forces present in nature are the electric fields and magnetic fields.

Question

A:1E IO ZV
6 11,1K/s ª,l| zain IQ
الكهربائية المحاضرة 1. . .
Solution / E at point P is equal to E, +E,
E = E+E.
E, = E1s +E
E, = E1y +E2y
5
Dr. Munther
Electricity
The University of Misan
College of Science
First year
Dr. Munther
E, = k,
cos 0 + k,
a +
cos 0 = 2k
cos e
E, = k
a + y
sin 0 - k.
a
sin 8 =0
cos A =4
2ag
E, = 2k,
(a² + y*)/Z
Q2/ A dipole with charges -q and +q, and separation 2a, is located on the X-axis with its
midpoint at the origin. A point charge Pis on the X-axis a distance r from the midpoint of the
dipole, what is the electric field on P due to the dipole?
inther

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