Q2] A vector is given by x = [-3.5 -5 6.2 11 0 8.1 -903-1 3 2.5]. Using conditional statements and a while loop, write a program that creates two vectors from x-one (call it P) that contains the positive elements of x, and a second (call it N) that contains the negative elements of x. In both P and N, the elements are in the same order as in x.
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- Write a function that accepts a number, N, and a vector of numbers, V. The function will return two vectors which will make up any pairs of numbers in the vector that add together to be N. Do this with nested loops so the the inner loop will search the vector for the number N-V(n) == V(m). n and m are indices in the vector of numbers. Example A = [1,2,3,4,5,6, 7] Google(5, A) Return [1,2,3,4] and [4,3,2,1] being the pairs that sum to 5. Notice that each pair appears twice. Try to write code that does not do this.Implement the following function without using any additional data structure, and without sorting the input vectors. /* Given two vectors of integers, check if the two vectors contain same set of values: e.g., V1=[3,4,10,4,10,11] and V2=[3,3,4, 11, 10] stores same set int: {3, 4, 10, 11}. Note that duplicates are removed when considering set */ @param list1, list2: two vectors of integers@pre: list1, list2 have been initialized@post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameSet (const vector<int> & list1, const vector<int> & list2) {//for each value in list1, check if it appears in list2, if not, return false //for each value in list2, check if the value appears in list1, if not return false //return true}Implement the following function, without using any data structure or #include <bits/stdc++.h> /* Given two vectors of chars, check if the two vectors are permutations of each other, i.e., they contains same values, in same or different order.e.g., V1=[‘a’,’b’,’a’] and V2=[‘b’,’a’,’a’] stores same multi-set of data points: i.e., both contains two ‘a’, and one ‘b’. e.g., V3=[‘a’,’c’,’t’,’a’] and V4=[‘a’,’c’,’t’] are not same multi-set. V3 contains two ‘a’s, while V4 has only one ‘a’. Note: when considering multiset, the number of occurrences matters. @param list1, list2: two vectors of chars @pre: list1, list2 have been initialized @post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameMultiSet (vector<char> list1, vector<char> list2) THIS IS NOT THE CORRECT SOLUTION / include headers #include <bits/stdc++.h> // deinfe the namespace using namespace std; // function fo rchecking same bool…
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- A university uses student numbers consisting of 6 digits plus a check digit in the 7th position. The check digit is found by taking the number formed by the first 6 digits modulo 7. A transposition in this setup is a switch of two adjacent digits - check digit excluded. Which transpositions of a student number (a6,a5,a4,a3,a2,a1,a0) (here written as a vector, with check digit a0) will not be detected by the check digit? Explain your answer in full and show any calculations you do. Hint: Note that the value of any ai in the number is ai×10i and consider the difference between the values of the correct and incorrect numbers modulo 7.Can you help me write a C++ program to do the following: Create a function append(v, a, n) that adds to the end of vector v a copy of all the elements of array a. For example, if v contains 1, 2, 3, and a contains 4, 5, 6, then v will end up containing 1, 2, 3, 4, 5,6. The argument n is the size of the array. The argument v is a vector ofintegers and a is an array of integers. Write a test driverCould you help me write a C++ code to do the following: Experiment with the following STL algorithms. More precisely,write a test driver that uses each algorithm on a vector of integers anda vector of strings. Both of these algorithms are defined in the library filealgorithm and included in the std namespace. (a) replace(start, stop, x, y) replaces all occurrences of element x by a copy of element y in the range [start,stop). Uses ==on elements.(b) max_element(start, stop) returns an iterator that points tothe maximum element in the range [start,stop). Returns stopif the range is empty. Uses < on elements