Q2 The figure below gives the grain-size distribution of twa soils. 100 80 Soil A 60 Soil B 40 20 1.0 0.1 0.01 0.001 Particle diameter (mm)-log scale The liquid and plastic limits of minus No. 40 sieve fraction of the soils are as follows: Soil A Soil B Liquid limit 30 26 Activate Winde Goettng Plastic limit 22 20 aCt Classify the soils according to USCS and ASTM-CS. Percent finer

Q2 The figure below gives the grain-size distribution of twa soils. 100 80 Soil A 60 Soil B 40 20 1.0 0.1 0.01 0.001 Particle diameter (mm)-log scale The liquid and plastic limits of minus No. 40 sieve fraction of the soils are as follows: Soil A Soil B Liquid limit 30 26 Activate Winde Goettng Plastic limit 22 20 aCt Classify the soils according to USCS and ASTM-CS. Percent finer

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Grain size distributions curves are given for 9 soils in Figures 1, 2 and 3. The LiquidLimit and Plastic Limit for the fine-grained portion of these soils are given in Table 1.a) Classify the soils according to ASTM/USCS (i.e., give both the Group Symboland Group Name).b) It is proposed that Soil 3 (Figure 2) be used for a highway subgrade. What is theAASHTO soil classification for this soil (see classification table on the last page ofthis assignment)? What is this soil's general rating as a subgrade?
Afine-grainedsoilisfoundtohavealiquidlimitof70%andaplasticlimitof38%. (a) On the plasticity chart for the Unified Soil Classification System, what soil type is this?(b) On the plasticity chart for the AASHTO classification system, what soil type is this?
Sieve # Maas retained (gr) 4 0 10 11,5 16 11,7 20 12 30 12,9 40 17,8 50 19,1 70 35,1 100 38,1 200 118 Pan 335 Draw grain size distribution curve,find D60, D30, D10 Classify the soil
From the particle size distribution curve, about 61% of the oil is finer than 0.074 mm in diameter. The liquid limit and plastic limit of minus No 40 fraction of the soils are as follows: LL =26, PL= 20. Classify the soil using the USCS.a. CL-MLb. CL-MLc. SP-SCd. CH
Soil Mechanics Based on the sieve analysis a soil has % finer for the following sieves: No. 10- 84% ; No. 40- 71% and No. 200- 64%. The liquid limit is 41 and Plasticity index is 14. Classify the soil by AASHT0 classification and give also the group index. a. A-6 (9) b. A-7-6(8) c. A-6 (5) d. A-7-5(8)
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For a given sieve analyis: No. 4 - % finer 100%, for No. 200 -%finer 86. LL=55, PL= 28. Classify the soil using USCS. Justify your answer.
The soil at a borrow area is at moisture content of 8.5%and unit weight of 17.5 kN/m3. This soil is used in the construction of a compacted road base where the dry unitweight is 19.5 kN/m3 and the moisture content is 14.0%. Ifthe finished volume of the road base is 120,000 m3, whatwould be the volume of the soil removed from the borrowpit? How much water would be added to the soil from theborrow pit?
Classify the group symbol of the soil by USCS using the data given below: Percent passing the #4 sieve 68 Percent passing the #200 sieve 22 Liquid Limit 34 Plastic Limit 17 Group of answer choices SM SW SP SC
1. Calculate the amount of CaCO3 required to raise the pH of a hectare of this soil to pH6? (X-axis) Weight of lime added to 250g soil: 0,1,2,3,4,5. (Y- axis) pH: 3.58,5.05,6.56,6.76,6.94,6.96, respectively. 2. How many kg P/ha is 20 ppm P? ha= 2x 10^6; P= phosphorus
Q 03: (a) Draw graph (using graph paper or excel) for soil 1 and 2 given in problem 2 and paste it in the following?(b) Calculate D10 D30 and D60 for Sieve Analysis plot in section (a) and calculate Coefficient of Uniformity and Coefficient of curvature for both soils. Also comment if the soils are well graded or poorly graded and which soil is better graded in comparing to other in case of soil 1 and 2.