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- #2. (a)Explain briefly the advantages of Gauss’ law over Coulomb’s law for thecalculation of the electric field.(b)A spherical ball of charged particles has a uniform charge density throughoutits volume. If the radius of the ball is 10 cm, find the radial distance both inside and outsidethe sphere where the electric field is one-third of the maximum electric field.What are the strength and direction of the electric field at the position indicated by the dot in the figure A) What is the strength of the electric field? Let r = 5.4 cm. B)Specify the direction of the electric field as an angle below the horizontal.13. Consider an electron and the surface that encloses it in Figure A. What is the electric flux through this surface?
- An O2- ion is levitating near Earth's surface, thanks to an electric field. Take gravity into consideration. a) What is the direction of the electric field at the location of the ion? b) What is the magnitude of the electric field at the location of the ion?A. What is the strength of the electric field at the position indicated by the dot in (Figure 1)? B.What is the direction of the electric field at that position? Specify the direction as an angle below horizontal.An electron is launched at a 45º angle and a speed of 5.0x106 m/s from the positive plate of the parallel-plate capacitor shown in the figure. The electron lands 4.0 cm away. a) What is the electric field strength inside the capacitor? b) What is the minimum spacing between the plates?
- If Q1 and Q2 are both negative in sample problem number 4, what would be the net electric field halfway between them?A thundercloud produces a vertical electric field of magnitude 2800N/C at ground level. You hold 22.0cm x 28.0cm sheet of paper horizontally below the cloud. (a) What is the electric flux through the sheet?(b) What would the flux be if you tilt the sheet of paper by 30°? (c) What would the flux be if you hold the sheet of paper vertically?The electric field at a distance of 0.154 m from the surface of an insulating solid sphere of radius 0.385 m is 1970 N/C. Assuming that the charge on the sphere is uniformly distributed, a) what is the charge density within it? b) Calculate the electric field inside the sphere at a distance of 0.150 m from the center.
- a) What is the electric field strength in a distance of 10.0 um to the right of charge q3?If the hemisphere (surface C) in Figure 25.10 (page 760) is tilted so that its disk-shaped cross section makes a 25 angle with the electric field, what is the electric flux through the hemisphere? Use Example 25.1 to check your result.Figure P25.29 shows a wry long tube of inner radius a and outer radius b that has uniform volume charge density . Find an expression for the electric field between the walls of the tubethat is, for a r b. Figure P25.29