Q2. (a) Prove Theorem 9 of the book. (Hint: Use moment generating function (m.g.f.). (b) Prove Theorem 10 of the book. (Hint: Use moment generating function (m.g.f.)). (c) Prove the identity E(X - H)? = E-1(X; – X)² + n (X – H)?.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 77E
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Q2. (a) Prove Theorem 9 of the book. (Hint: Use moment generating function (m.g.f.)).
(b) Prove Theorem 10 of the book. (Hint: Use moment generating function (m.g.f.)).
(c) Prove the identity E(X - H)? = E,(X; – X)² + n (X – H)?.
Transcribed Image Text:Q2. (a) Prove Theorem 9 of the book. (Hint: Use moment generating function (m.g.f.)). (b) Prove Theorem 10 of the book. (Hint: Use moment generating function (m.g.f.)). (c) Prove the identity E(X - H)? = E,(X; – X)² + n (X – H)?.
THEOREM 9. If X1. X2,...,X, are independent random variables having
chi-square distributions with vi, v2,..., Vn degrees of freedom, then
Y = EX;
i=1
has the chi-square distribution with vi + v2+ +n degrees of freedom.
THEOREM 10. If X and X2 are independent random variables, X1
has a chi-square distribution with vi degrees of freedom, and X1+ X2 has
a chi-square distribution with v> v degrees of freedom, then X2 has a
chi-square distribution with v-v degrees of freedom.
Transcribed Image Text:THEOREM 9. If X1. X2,...,X, are independent random variables having chi-square distributions with vi, v2,..., Vn degrees of freedom, then Y = EX; i=1 has the chi-square distribution with vi + v2+ +n degrees of freedom. THEOREM 10. If X and X2 are independent random variables, X1 has a chi-square distribution with vi degrees of freedom, and X1+ X2 has a chi-square distribution with v> v degrees of freedom, then X2 has a chi-square distribution with v-v degrees of freedom.
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