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Q3. A pump is required to pump water from a large reservoir to the water tower located 20 m above the reservoir (Figure 1). If 0.03 m /s of water having a density of 1000 kg/m³ is pumped through a 30-mm pipe. a. How much power is required to be delivered to the water by the pump? Consider the flow losses in the pipe; do the necessary assumptions. b. Determine the efficiency of the pump

Q3. A pump is required to pump water from a large reservoir to the water tower located 20 m above the reservoir (Figure 1). If 0.03 m /s of water having a density of 1000 kg/m³ is pumped through a 30-mm pipe. a. How much power is required to be delivered to the water by the pump? Consider the flow losses in the pipe; do the necessary assumptions. b. Determine the efficiency of the pump

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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F E D Water Tower Hydraulics Pump A Figure 1 Water Supply and Distribution System ¢ ¢ ¢ ¢ ¢ B. ¢ ¢ ¢ ¢ ¢
Transcribed Image Text:F E D Water Tower Hydraulics Pump A Figure 1 Water Supply and Distribution System ¢ ¢ ¢ ¢ ¢ B. ¢ ¢ ¢ ¢ ¢
Q3. A pump is required to pump water from a large reservoir to the water tower located 20 m above the reservoir (Figure 1). If 0.03 m³/s of water having a density of 1000 kg/m3 is pumped through a 30-mm pipe. а. How much power is required to be delivered to the water by the pump? Consider the flow losses in the pipe; do the necessary assumptions. b. Determine the efficiency of the pump
Transcribed Image Text:Q3. A pump is required to pump water from a large reservoir to the water tower located 20 m above the reservoir (Figure 1). If 0.03 m³/s of water having a density of 1000 kg/m3 is pumped through a 30-mm pipe. а. How much power is required to be delivered to the water by the pump? Consider the flow losses in the pipe; do the necessary assumptions. b. Determine the efficiency of the pump
Expert Solution
Step 1

a) 

The expression for energy between velocity 1 and 2 is given as

P1γ+V122g+z1+HP=P2γ+V222g+z2

P1γ+02g+0+HP=P1γ+V222g+Z2HP=V222g+Z2

Substitute the value in above expression

HP=0.03π0.032/42×9.81+20HP=125.341 m

The expression for horse power is given as

Power=HP×Q×γ

Substitute the value in above expression

Power=125.341×0.03×1000×9.81Power=36888 wattsPower=36.888 kW

Therefor 36.88 kW power is required to be delivered to the water.

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