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- I need a step by step answer please on howe we do substitute and make d^2 as the subject of the equation. Thank you :)Do not solve this with 0 temperature BCs, instead solve with the following BCs: u(0, t) = 0, u(L, t) = -20.Circle final answer Question: Which series helps us to derive the discretized form of the governing equations? Remember to circle final answer
- ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ʜᴇʟᴍʜᴏʟᴛᴢ ᴀʙꜱᴏʟᴜᴛᴇ ᴠɪꜱᴄᴏꜱɪᴛʏ ᴏꜰ ᴡᴀᴛᴇʀ ᴀᴛ 670°ʀ?ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ᴡᴇɪɢʜᴛ ɪɴ ʟʙꜰ ᴏꜰ ᴀ ʟɪQᴜɪᴅ ᴛʜᴀᴛ ʜᴀꜱ ᴀ ᴍᴀꜱꜱ ᴏꜰ 30ʟʙᴍ ᴏɴ ᴇᴀʀᴛʜ ᴡɪᴛʜ ɢ=32.174ꜰᴛ/ꜱ2? ᴡᴇɪɢʜᴛ ɪɴ ʟʙꜰ ɪꜰ ᴛʜᴇ ɢ=29ꜰᴛ/ꜱ2? I will give like thanks!Here I'm finding final kinetic energy KE2, given initial kinetic energy, initial force, alpha N/m^3 and beta N representing F(x). I integrated F(x)dx though I'm not sure how to integrate Fo with respect to X. I tried just finding the integrand ouput of 7.5x10^4m and subtracting the initial force, since the initial force would count as x=0, or I assumed. I then followed the regular approach of adding over the initial KE1 to isolate the unknown KE2 which I keeo getting as 1.07x10^10 which seems to be off. Again, I suspect where I'm going wrong is integrating the initial force -3.5x10^6N with respect to x, but other than what I've already done, that doesn't make sense to me.Answer no. 17, given the number 16 below. The computed Q and time in 16 are, Q= 15 862.7953 kJ, t=143. 1397 mins. Derive with the formula below, show the cancellation, explain the step by step and DRAW a free body diagram/figure. refer with this: PE1 + KE1 + U1 + WF1 + Q1 + W1 = PE2 + KE2 + U2 + WF2 + Q2 + W2 + E losses.
- The horizontal force due to water acting on the bolt (Fh): Fh=ρ×A1×V1×V1--V2 Fh=1000×π4×0.0752×1.254×1.254+11.286( Fh)=69.472 This is the only part I did not understand how to get. Can you please explain more? I arrived with this equation, -P1A1 - P2A2 (cancelled since atmos. Pres.) +Fh = rho A1v1 (v2-v1) Why did P1A1 disappear in your solution? How did you come up with (v1 - - v2) ? What is the control volume? Why did you not do a summation of forces is equal to change in momentum but instead go immediately to getting the horizontal force acting on the bolt?I just need help simplifying these equations (1 and 2). Qo,Kic, and CL are all their own variables (not 2 multiplied ie. Q*o, k*i*c and not C*L)ᴘᴀʀᴛ ᴀ.ᴀ ᴋɴᴜᴄᴋʟᴇ ᴊᴏɪɴᴛ ɪꜱ ᴛᴏ ʙᴇ ᴀxɪᴀʟʟʏ ʟᴏᴀᴅᴇᴅ ᴡɪᴛʜ ᴀ ᴛᴇɴꜱɪʟᴇ ʟᴏᴀᴅ ꜰ. ᴛʜᴇ ᴀꜱꜱᴇᴍʙʟʏ ᴏꜰ ᴘᴀʀᴛꜱ ᴀɴᴅ ᴛʜᴇɪʀ ᴠᴀʀɪᴀʙʟᴇᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴀʀᴇ ꜱʜᴏᴡɴ ɪɴ ᴛʜᴇ ꜰɪɢᴜʀᴇ ʙᴇʟᴏᴡ. ᴡʀɪᴛᴇ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴ ᴀᴛ ᴇᴀᴄʜ ᴏꜰ ᴛʜᴇ ᴘᴏꜱꜱɪʙʟᴇ ʟᴏᴄᴀᴛɪᴏɴꜱ ᴏꜰ ꜰᴀɪʟᴜʀᴇ. ɪᴅᴇɴᴛɪꜰʏ ᴇᴀᴄʜ ꜱᴛʀᴇꜱꜱ ᴀɴᴅ ᴡʀɪᴛᴇ ɪᴛꜱ ᴇQᴜᴀᴛɪᴏɴ ɪɴ ᴛᴇʀᴍꜱ ᴏꜰ ᴛʜᴇ ʟᴏᴀᴅ ꜰ, ᴀɴᴅ ᴛʜᴇ ɢɪᴠᴇɴ ᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴀ, ʙ, ᴄ, ᴅ, ᴋ, ᴍ ᴀɴᴅ ɴ. (ᴇxᴀᴍᴘʟᴇ: ᴛᴇɴꜱɪʟᴇ ꜱᴛʀᴇꜱꜱ ᴀᴛ ᴛʜᴇ ʀᴏᴅ ᴏꜰ ᴛʜᴇ ᴋɴᴜᴄᴋʟᴇ ᴊᴏɪɴᴛ: ꜱᴛ = 4ꜰ/Πᴅ2). ᴅᴏɴ’ᴛ ᴜꜱᴇ ᴠᴀʀɪᴀʙʟᴇꜱ ᴛʜᴀᴛ ᴀʀᴇ ɴᴏᴛ ᴅᴇꜰɪɴᴇᴅ ɪɴ ᴛʜᴇ ᴊᴏɪɴᴛ ᴅᴇꜱᴄʀɪʙᴇᴅ ʙᴇʟᴏᴡ. ꜱᴜᴘᴘᴏʀᴛ ᴇᴀᴄʜ ᴏꜰ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴꜱ ʙʏ ᴍᴇᴀɴꜱ ᴏꜰ ᴀɴ ɪꜱᴏᴍᴇᴛʀɪᴄ ᴅʀᴀᴡɪɴɢ ɪɴᴅɪᴄᴀᴛɪɴɢ ᴛʜᴇ ᴘᴀʀᴛ ᴀɴᴅ ɪᴛꜱ ᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴛʜᴀᴛ ᴍɪɢʜᴛ ʜᴀᴠᴇ ꜰᴀɪʟᴇᴅ ᴅᴜᴇ ᴛᴏ ᴏᴠᴇʀꜱᴛʀᴇꜱꜱɪɴɢ. ꜰᴏʀ ᴛʜᴇ ʙᴇɴᴅɪɴɢ ꜱᴛʀᴇꜱꜱ ɪɴ ᴛʜᴇ ᴘɪɴ, ᴄᴏɴꜱɪᴅᴇʀ ᴛʜᴇ ʟᴏᴀᴅꜱ ᴛᴏ ʙᴇ ᴜɴɪꜰᴏʀᴍʟʏ ᴅɪꜱᴛʀɪʙᴜᴛᴇᴅ ᴀᴛ ᴛʜᴇ ᴄᴇɴᴛᴇʀ ᴏꜰ ᴛʜᴇ ᴄᴏᴛᴛᴇʀ ᴀɴᴅ ᴜɴɪꜰᴏʀᴍʟʏ ᴠᴀʀʏɪɴɢ ᴀᴛ ᴛʜᴇ ᴋɴᴜᴄᴋʟᴇ ᴇɴᴅ. ɴᴇɢʟᴇᴄᴛ ᴛʜᴇ ᴘʀᴇꜱᴇɴᴛ ᴏꜰ ᴛʜᴇ ꜰɪʟʟᴇᴛꜱ ɪɴ ᴄᴏɴꜱɪᴅᴇʀɪɴɢ ᴛʜᴇ ᴅɪᴍᴇɴꜱɪᴏɴꜱᴘᴀʀᴛ ʙ.ᴜꜱɪɴɢ ᴛʜᴇ ꜱᴛʀᴇꜱꜱ ᴇQᴜᴀᴛɪᴏɴꜱ ꜰᴏʀᴍᴇᴅ ɪɴ ᴘᴀʀᴛ ᴀ, ᴅᴇꜱɪɢɴ ᴛʜᴇ ᴊᴏɪɴᴛ ʙʏ ꜱᴘᴇᴄɪꜰʏɪɴɢ ᴛʜᴇ ʀᴇQᴜɪʀᴇᴅ ᴅɪᴍᴇɴꜱɪᴏɴꜱ ᴏꜰ ᴛʜᴇ ᴘᴀʀᴛꜱ. ᴛʜᴇ ᴊᴏɪɴᴛ ɪꜱ ᴛᴏ ʜᴀɴᴅʟᴇ ᴀ…
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