Here I'm finding final kinetic energy KE2, given initial kinetic energy, initial force, alpha N/m^3 and beta N representing F(x). I integrated F(x)dx though I'm not sure how to integrate Fo with respect to X. I tried just finding the integrand ouput of 7.5x10^4m and subtracting the initial force, since the initial force would count as x=0, or I assumed. I then followed the regular approach of adding over the initial KE1 to isolate the unknown KE2 which I keeo getting as 1.07x10^10 which seems to be off. Again, I suspect where I'm going wrong is integrating the initial force -3.5x10^6N with respect to x, but other than what I've already done, that doesn't make sense to me.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Here I'm finding final kinetic energy KE2, given initial kinetic energy, initial force, alpha N/m^3 and beta N representing F(x). I integrated F(x)dx though I'm not sure how to integrate Fo with respect to X. I tried just finding the integrand ouput of 7.5x10^4m and subtracting the initial force, since the initial force would count as x=0, or I assumed. I then followed the regular approach of adding over the initial KE1 to isolate the unknown KE2 which I keeo getting as 1.07x10^10 which seems to be off. Again, I suspect where I'm going wrong is integrating the initial force -3.5x10^6N with respect to x, but other than what I've already done, that doesn't make sense to me. 

15=1 N.m
KEz- KE,= S, FW)dx
Fo--3.5×10°N
F(X) = or x3+ B, where a=6.1 ×10°N/m³
B = -4.1 x 1ON
- 7. 5× 10°m
KE,- 2.7×10J = | 6.x10° NIm>x}-4]*10°N dx
(즉x" * Bx)
Transcribed Image Text:15=1 N.m KEz- KE,= S, FW)dx Fo--3.5×10°N F(X) = or x3+ B, where a=6.1 ×10°N/m³ B = -4.1 x 1ON - 7. 5× 10°m KE,- 2.7×10J = | 6.x10° NIm>x}-4]*10°N dx (즉x" * Bx)
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