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- 1.Implement Thirsty problem using semaphore . Scenario:To drink, a thirsty person must have three things; water, ice and a glass.There are three thirsty people, each having a different one (and only one) of the three required items. A fourth person, a server has unlimited supply of all three items. If nobody is drinking, the server places two of the three items (chosen at random) onto table. Thirsty person who can make a drink from those two items will pick them up and drink a glass of ice water. When done, thirsty person will notify the server and the process will repeat.Let l(x) be "x has an internet conection" and C(x, y) be "x and y have chatted over the internet". Assume the domain is all students in a class. Express the following using quantifiers. 1. Jerry does not have an internet connection 2. Exactly one student in the class has an internet connection 3. Someone in your class has an internet connection but has not chatted with anyone else in the class.QUESTION THREEConsider the thirsty person problem given below: To drink, a thirsty person must have three things; water, ice and a glass. There are three thirsty people, each having a different one (and only one) of the three required items. A fourth person, a server has unlimited supply of all three items. If nobody is drinking, the server places two of the three items (chosen at random) onto table. Thirsty person who can make a drink from those two items will pick them up and drink a glass of ice water. When done, thirsty person will notify the server and the process will repeat. Write a process that will control the thirsty person and the server using semaphores. (i) What is a critical section in code?Explain the three properties that any solution to the Critical Section Problem should guarantee.Explain the role the Operating System plays in Garbage-In-Garbage-Out (GIGO).
- Q. There is an island that has two kinds of inhabitants, knights, who always tellthe truth, and their opposites, knaves, who always lie. It is assumed that every inhabitant of theisland is either a knight or a knave. Below there are 3 inhabitants, who are denoted by A, B andC.A. What are A, B and C if A says “If B is a knave then C is a knave”, and B says “If Cis a knight then A is a knave”? Briefly explain your reasoning.B. What are A,B and C if A says “B is a knight and C is a knight”, and B says “A is aknight if and only if C is a knave”? Briefly explain your reasoning.AI a modern approach 10.3 The monkey-and-bananas problem is faced by a monkey in a laboratory with some bananas hanging out of reach from the ceiling. A box is available that will enable the monkey to reach the bananas if he climbs on it. Initially, the monkey is at A, the bananas at B, and the box at C. The monkey and box have height Low, but if the monkey climbs onto the box he will have height High, the same as the bananas. The actions available to the monkey include Go from one place to another, Push an object from one place to another, ClimbUp onto or ClimbDown from an object, and Grasp or Ungrasp an object. The result of a Grasp is that the monkey holds the object if the monkey and object are in the same place at the same height. a. Write down the initial state description.b. Write the six action schemas.c. Suppose the monkey wants to fool the scientists, who are off to tea, by grabbing the bananas, but leaving the box in its original place. Write this as a general goal (i.e.,…Exercise 4 On a certain island there are only two types of people: Knights and Knaves. Every person on the island is either is a Knight or a Knave, an no one is both. When the people on the island speak, the following rules hold: Knights always tell the truth. Knaves always lie. There are two native islanders standing next to each other. One is named Claire and the other is named Desmond. You do not know what type either of them are. Claire suddenly says, “We are both Knights”. After this, Desmond says “Either Claire is a Knight or I am a Knight, but we are not both Knights.” What is Claire? Is it possible to determine what Desmond is?
- Prolog Consider the (directed) network in the attached document. We could represent this network with the following Prolog statements: link(a,b). link(a,c). link(b,c). link(b,d). link(c,d). link(d,e). link(d,f). link(e,f). link(f,g). Now, given this network, we say that there is a "connection" from a node "X" to a node "Y" if we can get from "X" to "Y" via a series of links, for example, in this network, there is a connection from "a" to "d", and a connection from "c" to "f", etc. Formulate the appropriate Prolog rule "connection(X,Y)" which is true if (and only if) there is a "connection" from "X" to "Y" as described above --- note that this rule will be recursive. Test this rule out on the above network, to see if it is working correctly. Once it is working correctly, you will note that, e.g., the query "connection(a,e)." will give "true" multiple times. This means something, actually:The Philosophers' Dinner Problem Five philosophers sit around a table and spend their lives dining and thinking. Each philosopher has a bowl of noodles and a fork to the left of your plate. To eat the noodles you need two forks and each philosopher you can only take the ones to your left and right. If any philosopher takes a fork and the other is busy, he will wait, fork in hand, until pick up the other fork, so you can start eating later. If two adjacent philosophers try to pick up the same fork at the same time, a race condition: they both compete to take the same fork, and one of them left without eating. If all the philosophers take the fork to their right at the same time, then everyone will be waiting forever, because someone must release the fork that is lack. No one will because everyone is in the same situation (hoping that someone put down their forks). Then the philosophers will starve. This lock mutual is called deadlock or deadlock. The problem is to find an algorithm that…strcit warning answer only u know else skip dont post existing strict action
- Correct answer will be upvoted else downvoted. Computer science. Child Ehab has a piece of Cut and Stick with an exhibit an of length n composed on it. He intends to snatch some scissors and do the accompanying to it: pick a reach (l,r) and cut out each component al, al+1, ..., ar in this reach; stick a portion of the components together in a similar request they were in the exhibit; end up with different pieces, where each piece contains a portion of the components and each component has a place with some piece. All the more officially, he segments the arrangement al, al+1, ..., ar into aftereffects. He thinks a dividing is lovely if for each piece (aftereffect) it holds that, assuming it has length x, no worth happens rigorously more than ⌈x2⌉ times in it. He didn't pick a reach yet, so he's pondering: for q ranges (l,r), what is the base number of pieces he really wants to parcel the components al, al+1, ..., ar into with the goal that the dividing is delightful.…A) quadrant [★★] Complete the quadrant function below, which should return the quadrant of the given x, y point according to the diagram on the right (borrowed from Wikipedia). Points that lie on an axis do not belong to any quandrant. Hints: (a) define a helper function for the sign of an integer, (b) match against a pair. type quad = I | II | III | IV type sign = Neg | Zero | Pos let sign (x:int) : sign = ... let quadrant : int*int -> quad option = fun (x,y) -> match ... with | ... -> Some I | ... -> Some II | ... -> Some III | ... -> Some IV | ... -> None B) quadrant when [★★] Rewrite the quadrant function to use the when syntax. You won’t need your helper function from before. let quadrant_when : int*int -> quad option = function | ... when ... -> Some I | ... when ... -> Some II | ... when ... -> Some III | ... when ... -> Some IV | ... -> None please use Ocaml for the codeIndian cricket team Players at an winning celebration dine at a circular table on which there is a single fork between each Player. Players either eat or think, and always start dinner thinking. To eat, a Player first picks up the fork immediately to his left and, once successful, picks up the fork immediately to his right. When a required fork is not on the table, the Player waits, neither eating nor thinking, until the fork is returned to the table. After eating, a Player returns both forks to the table. No cutlery is required to think. Your task is to model the above scenario in Java. (a) Write a class called Fork with two public methods, ForkpickUp and ForkputDown. The methods should take no arguments and return no result. An instance of Fork should act as a lock to prevent concurrent access. In other words, once ForkpickUp has been called, all further calls to ForkpickUp should block until ForkputDown is called; when ForkputDown is called, one caller (if any) who is blocked should…
