Q6: For 8051 system of 11.0592 MHz, find how long it takes to execute e instruction. CLO-3 a. MOV R3, #55 b. DEC R3 c. DJNZ R2 d. LJMP e. SJMP
Q: After the SHR instruction is executed in the code sequence below, what is the final value for AL?…
A: Correct Option is B⇒ 0010_1011
Q: 02: (A) Find the phicycal address if (BP) = 00100H. (SI) = 0200H, (SS) = 2000H and a displacement of…
A: Note :- ******************************************* As per our guidelines we are supposed to answer…
Q: 8. Write equivalent instruction sequences using string instructions or each of the following: a) MOV…
A: Given data is shown below:
Q: 12. What is the content value for instruction address 803? * PC 804 AC 804 АС 1CC6 PC D4CA IR 5913…
A: Program counter PC stores the address of next instruction. Given address of current instruction is…
Q: The physical address of the following memory location specified in the instruction MOV [BX-0200H],…
A: The physical address for the instruction MOV [BX + 0200H], AL is 61200H.
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
Q: Assume that AO - SN where N is your student number, and X is the sum of the least significant four…
A: MOVE.L INSTRUCTION Syntax: MOVE.L l,D0 Move the content of memory location l into D0. Given…
Q: If the first instruction "LXI H, 1100H" is positioned at address 7000H in memory, at what address…
A:
Q: Q: For a basic computer that is currently running in its timing TO of execution for an instruction…
A: According to the information given:- We have to find the next instruction after end of the…
Q: Q: For a basic computer that is currently running in its timing TO of execution for an instruction…
A: [mem loc: contents] =[365:9473],[366:7010],[367:5431],[368:4620],[431:1A23],[620:C80D]
Q: Write the machine code encoding of the assembly instruction: 'mrmovq 0x230 (%rax), %rcx". w w'…
A: Below is the solution:
Q: corresponding Which one of the following is the binary representation of the machine code that to…
A: Given that, opcode of lw = 35 register is $t1=9 register $t2= 10 lw $t1, 20($t2)
Q: 26. Find the time delay in the following program if the crystal frequency is 1 MHz. Do not ignore…
A:
Q: Two unsigned words integers are stored at the physical memory addresses 00B00 and OOB01…
A: The Answer is in given below steps
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: the given instruction is MOV EIP, [BP+BAFDH] ; ( It is not a valid instruction, because EIP can not…
Q: Q: For a basic computer that is currently running in its timing TO of execution for an instruction…
A: Lets see the solution in the next steps
Q: Q4) Suppose that DS-1020H, SS-2010H, BX-0300H, BP-1010H, and DI= 1100H. Determine the memory address…
A: Given that, DS=1020H SS=2010H BX=0300H BP=1010H and DI=1100H Given Instructions are:MOV [DI+300], AL…
Q: Ques. if the number of general purpose registers (e.g. $t0, $a0, etc.) was increased to 64, then the…
A: The answer is True.
Q: We have this assembly code: org 8000h ld a,5 loop: dec a jp p, loop halt When using the Z80…
A: The loop will execute 6 times. jp stands for jump positive. it continues the loop until a is…
Q: After the SHR instruction is executed in the code sequence below, what is the final value for AL?…
A: Given: After the SHR instruction is executed in the code the final value for AL is:
Q: 3) Assume SS=5000H, DS=6000H, ES=7000H, CS=9000H, BX=100OH, DI=2000H, BP=3000H, IP=4000H, SI=2000H,…
A: Finding the physical address MOV 30.[SI], AL Here we are given that DS = 6000H Shifting left 20…
Q: If a MIPS instruction code is: 000000 10001 10010 01000 00000 100000 What is the instruction? Select…
A: Step 1 The answer is given in the below step.
Q: Q3) If BP=1000, DS=0400, SS=0700, CS=0500 and AL=EDH, for the following instruction: MOV [BP] +…
A: It is defined as a physical location of required data in a memory. The user never directly deals…
Q: Given that SI contains 0050H. If after executing the instruction MOV [SIJ, AH the content of AH is…
A: Answer: The content of DS is added to the offset.
Q: 10- Execute each instruction below and show the result of the registers. MOV AX, 453ЕН MOV BX, 1234H…
A: According to the information given:- We have to find the register values of after execution.
Q: 5. If the state of 8086 is as follows : (SI) = 0500 H (DS: 0500 H) = 00 H (DS: 0501 H) = 10 H…
A: (SI)=0500H (DS:0500 H) =00 (DS: 0501 H) =10 H Executing each instruction below a) JMP 10 H b)…
Q: How many times the instruction (MUL DX) is executed? MOV CX, OFFFFH MOV DX, 0458H SSS: MOV AX, 0023H…
A: The instruction (MUL DX) is executed
Q: Q: For a basic computer that is currently running in its timing TO of execution for an instruction…
A: The solution to the given problem is below
Q: Q: For a basic computer that is currently running in its timing TO of execution for an instruction…
A: Lets see the solution in the next steps
Q: 16. If the first instruction "LXI H, 1100H" is positioned at address 7000H in memory, at what…
A: Correct answer of above given question is Option(1) 7003H i.e next instruction is located at address…
Q: Q: For a basic computer that is currently running in its timing TO of execution for an instruction…
A: Answer: I have given answer in the brief explanation
Q: Q2) The 8-bit registers A, B, C & D are loaded with the value (F2) hex. (FF) hex+ (B9) hex and (EA)…
A: Lets us calculate the value of the registers , A= (F2)hex= (11110010) B= (FF)hex= (11111111)…
Q: f you have AX-0208H, BL-D8H, the results of performingII a. 00F3 H b. F300 H c. 5802 H d. 0258 H he…
A: 3. If you have AX=0208H, BL=D8H, the result of performing IDIV BL in AX is: a. 00F3H…
Q: Example: The content of PC in the simple computer is 3AFU. The content of AC is 6ECSH. The content…
A: List of the initial conditions that are given below: AR IR 3AF 932E 32E 09AC…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: We have given an Instruction , we have to find the effective address , physical address , etc. Out…
Q: (A) Find the phicycal address if (BP)=0100H , (SI) = 0200H , (SS)= 2000H and a displacement f 10H,…
A: Below i have answered both question:
Q: Q.1- Make the right choice for the followings: 1. 8086 processor could be interfaced with memory…
A: The 8086 is a 16 bit microprocessor. The total number of output that are (a) 64 M The 8086 have 20…
Q: After the SHR instruction is executed in the code sequence below, what is the final value for AL?…
A: Option b is correct. Explanation MOV AL, 1010_1111b This instruction the value 1010_1111 to AL.
Q: NA. F
A: An assembly language is a programming language that usually has one instruction for the processor to…
Q: Assume SS=5000H, DS=6000H, ES=7000H, CS=9000H, BX=1000H, DI=2000H, BP=3000H, IP=4000H, SI=2000H, the…
A: Given: We are given various registers with values stored in them. Register such as SS, DS, ES, CS,…
Q: Memory locations 00390H through 00393H contain, respectively, 9A, 76, 65, and 1F. What does AX…
A: Memory location 00393H contain ,respectively,9A ,76,65 and 1F.what does Ax contain after each…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: the given instruction is MOV EIP, [BP+BAFDH] ; ( It is not a valid instruction, because EIP can…
Q: 1. SP=F002H; after PUSH BX, what is the value of SP? _____________ (1 Mark) 2. BL=00, after…
A:
Q: 1- The instruction : MOV [Dx+SI], Ax is allowed T 2- The instruction : MOV ES:[SI], Ax is not…
A: 1. True The instruction is valid 2. False The instruction is invalid, since in based index…
Q: When an instruction was CORRECTLY executed on the MIPS single-cycle CPU, we observed MemtoReg = 0,…
A: The answer to the above-given question is given below:
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: the given instruction is MOV EIP, [BP+BAFDH] ; ( It is not a valid instruction, because EIP can not…
Q: Suppose R1 contains 00c6 and R2 contains Odc1. What is the effective address in this instruction?…
A: Comparing R1 value 00c6 and R2 value 0dc1 Answer: R2 = 0dc1 is effective address in this instruction
Q: Q1) If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] +…
A: Given, BX =1000 DS =0200 SS =0100 CS =0300 AL =EDH Instruction = MOV [BX]+1234H,AL Physical…
Q: If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] + 1234H,…
A: Answer: It is a base addressing mode. Effective address of the operand obtained by adding direct or…
Q: he higher order bits of R2 and store it in R4.
A: RTL used to answer this question:
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- The MIPS assembly language command: add $t0, $s1, $s2 when converted to machine language code looks as follows: Opcode: 000000 rs: 10001 rt: 10010 rd: 01000 shamt: 00000 funct: 100000 Question: How many times will the Data Memory be read to execute this command? Select the best answer. Group of answer choices 0 1 2 3 This is a trick question! The answer depends on whether the values of the rs, rd, and rt are kept in the memory or in the local registersThis question was already asked on Bartleby however the two level table was not created. A computer system uses 16-bit addresses for virtual and physical addresses, and each page and frame has a size of 256 bytes. 1. suppose that the OS uses a two-level page table. Draw the page table using the same structure and logic as the image provided, from an article found online this logic can be anazyed through the link https://sonsh0824.tistory.com/entry/MultiLevel-Page-Table . (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.) 2. What is the size of the two-level page table given in question I(f)? 3. Now, translate the virtual addresses to physical…Computer Science Please answer this question in assembly language with .asm extension. The code given in 99Heater.asm file is: ; ===== Heater and Thermostst on Port 03 ==========================; ===== 99Heater.asm ==============================================; ===== Heater and Thermostst on Port 03 ========================== MOV AL,0 ; Code to turn the heater off OUT 03 ; Send code to the heater IN 03 ; Input from Port 03 AND AL,1 ; Mask off left seven bits JZ Cold ; If the result is zero, turn the heater on HALT ; Quit Cold: MOV AL,80 ; Code to turn the heater on OUT 03 ; Send code to the heater END; ================================================================= Fix the program 99Heater.asm so that the temperature will stay at 21 ºC. Please solve the question in assembly language. I will definitely give you THUMBS UP.
- What would the following look like in memory? Write the data values in hex and continue numbering for the addresses. AREA MyData, DATA stuff dcb 15, 0x15, "1", -5 ; info space 4 things dcd 0xCD8912AB, -5, 0xFB, 0xF00D ;use our default endianness stuff2 dcb 4, 0, 0, 0xC Address (in hex) Data (in hex) Label 0x20000000 0x20000001 0x20000002 0x20000003 ...onvert the following C code snippet into the corresponding x86 assembly instructions. 1) if(x error_outlineHomework solutions you need when you need them. Subscribe now.arrow_forward Question Asked Aug 11, 2020 1 views Convert the following C code snippet into the corresponding x86 assembly instructions. 1) int n = 5; for(int i = 0; i <= 10; i++) { cout<<n<<” x ”<<i<<” = ”<<n*i<<endl; }Topic: 8086 microprocessor Q 1c) AL= 53 CL=29 ADD AL, CL DAA What is the value of AL after execution? Q 1d) MOV AL, 4929H, what will be the value of AL after execution?
- Calculate Physical Address of Main memory • Given the contents of CS:IP = [3000H]:[100H] • Given the contents of SS:SP = [50A0H]:[300H] • Given the contents of ES:DI = [60C0H]:[200H] • Given the contents of DS:SI = [A1C0H]:[2F00H] • Given the contents [CS]:[IP]=[1F0AH]:[15A6H] • Given the contents [SS]:[SP]=[82FFH]:[0FA1H]Questions are from Microprocessor (8086)Siemens programming uses the letter 'Q' to indicate an output address. What letter does the Allen Bradley software use? (Just the letter for an answer)write an arm assembly 64 bit program IT HAS TO BE 64 BIT THE ONE ANSWERED BEFORE IS NOT 64 BIT implement a small program that parses a string stored in "my_number" into an integer (decimal number): ; "555" -> 555; ; The result should be stored in R8 ; '5' in ASCII code is represented by 0x35, the example below is "555" my_number DCD 0x00353535
- Walk through the assembly program below. Add comments where indicated that describe what is happening for the functional block of code that follows it. .DEF temp=R16 ; .DSEG Results: .byte 1 Param1: .byte 1 Param2: .byte 1 .CSEG .ORG 0x0000 RJMP setup .ORG 0x100 setup: LDI temp, LOW(ramend) OUT SPL, temp LDI temp, HIGH(ramend) OUT SPH, temp main: ; Write a comment describing the next four lines of code LDI temp, 0x0f STS Param1, temp LDI temp, 0x10 STS Param2, temp ; Write a comment describing the next five lines of code CALL calculate LDS temp, Results end: NOP RJMP end calculate: ; Write a comment describing the next four lines of code PUSH r17 PUSH r18 PUSH r0 PUSH r1 ; Write a comment describing the next five lines of code LDS r17, Param1 LDS r18, Param2 MUL r17, r18 OR r0, r1 STS Results, r0 ; Write a comment describing the next five lines of code POP r1 POP r0 POP r18 POP r17 RET0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h. Add the contents of memory location 451h to AC. Store AC to memory location 8h. Store AC to I/O device number 8h.Please do this question through https://cpulator.01xz.net/?sys=arm-de1soc Assembly language using ARM Write an assembly language program that uses 3 registers. R0,R1 and R2 . The registers should have values 2, 5, and 0, respectively. The program will add, sub, divide and multiply the contents of the Register R0 to that of R1 and store the result into R3.