Q7. What is the degeneracy of the fifth energy level of a cubic box? A. 1 B. 3 C. 2 D. 4 E. 6

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Chapter6: The Periodic Table And Atomic Structure
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Problem 6.93PAE: 6.93 A mercury atom is initially in its lowest possible (or ground state) energy level. The atom...
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Hi sir Please solve question 7

Q5. Calculate the wavelength of transition from n = 2 to n = 3 for a particle in one dimensional
box. The wavelength of transition from n = 1 to n = 2 for the particle occurs at 1.0 x10 m.
A. 3.0 x 10-5m
B. 6.0 x 10 m
C. 6.0 x 10 m
D. 3.0 x 10 m
E. 5.0 x 10 m
Q6. Which of the following statements is correct?
A. For a particle in one-dimensional box (n = 2) stationary state, the probability of
finding the particle in the left quarter of the box equals the probability of finding it in
the right quarter of the box.
B. The particle in one-dimensional box ground state has quantum number n = 0.
C. The particle in one-dimensional box stationary state wavefunctions are discontinuous
at certain points
D. The maximum probability density for every particle in one-dimensional box
stationary state is at the center of the box
E. For a particle in a one-dimensional box (n = 1) stationary state, the probability of
finding the particle in the left third of the box equals the probability of finding it in
the middle third of the box.
Q7. What is the degeneracy of the fifth energy level of a cubic box?
A. 1
B. 3
C. 2
D. 4
E. 6
Q8. Calculate the second ionization energy of He.
A) 8.71 x 10-21 J
B) 8.71 x 10-15 J
C) 8.71 x 10-18 J
D) -8.71 x 10-18 J
E) -8.71x 10-15 J
Q9. How many nodes are there in the wavefunction of a harmonic oscillator with v = 5?
A. 1
B. 2
C. 3
D. 4
E. 5
3
Transcribed Image Text:Q5. Calculate the wavelength of transition from n = 2 to n = 3 for a particle in one dimensional box. The wavelength of transition from n = 1 to n = 2 for the particle occurs at 1.0 x10 m. A. 3.0 x 10-5m B. 6.0 x 10 m C. 6.0 x 10 m D. 3.0 x 10 m E. 5.0 x 10 m Q6. Which of the following statements is correct? A. For a particle in one-dimensional box (n = 2) stationary state, the probability of finding the particle in the left quarter of the box equals the probability of finding it in the right quarter of the box. B. The particle in one-dimensional box ground state has quantum number n = 0. C. The particle in one-dimensional box stationary state wavefunctions are discontinuous at certain points D. The maximum probability density for every particle in one-dimensional box stationary state is at the center of the box E. For a particle in a one-dimensional box (n = 1) stationary state, the probability of finding the particle in the left third of the box equals the probability of finding it in the middle third of the box. Q7. What is the degeneracy of the fifth energy level of a cubic box? A. 1 B. 3 C. 2 D. 4 E. 6 Q8. Calculate the second ionization energy of He. A) 8.71 x 10-21 J B) 8.71 x 10-15 J C) 8.71 x 10-18 J D) -8.71 x 10-18 J E) -8.71x 10-15 J Q9. How many nodes are there in the wavefunction of a harmonic oscillator with v = 5? A. 1 B. 2 C. 3 D. 4 E. 5 3
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