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- Given the following SQL query: Student (sid, name, age, address) Book (bid, title, author) Checkout (sid, bid, date) SELECT S.name FROM Student S, Book B, Checkout C WHERE S.sid = C.sid AND B.bid = C.bid AND B.author = ’Olden Fames’ AND S.age > 12 AND S.age < 20 Write relational algebra query for the above SQL query. Using a drawing tool such as Visio or others (ex: https://www.draw.io/ is a free one) to draw initial relational algebra query trees for the query generated in question 1. Transform the initial query trees created above into a more efficient form (use the heuristic rules and show your steps (./* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…/* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…
- /* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…can you help me iwth these two queries in mySQL. Write a SQL statement to create a table job_history including columns employee_id, start_date, end_date, job_id and department_id and make sure that, the employee_id column does not contain any duplicate value at the time of insertion and the foreign key column job_id contain only those values which are exists in the jobs table. Write a SQL statement to create a table employees including columns employee_id, first_name, last_name, email, phone_number hire_date, job_id, salary, commission, manager_id and department_id and make sure that, the employee_id column does not contain any duplicate value at the time of insertion and the foreign key columns combined by department_id and manager_id columns contain only those unique combination values, which combinations are exists in the departments table.This is a database system question regarding SELECT: Which of the following statements is true for SELECT statements in general? a. HAVING is executed before WHERE when running an SQL query b. SELECT is executed before FROM when running an SQL query c. Each SELECT clause must have a WHERE clause as well. d. COUNT(column_name) function returns the number of values in the column, including any NULLs e. HAVING clause specifies a condition for selecting grouped tuples from the GROUP BY clause.
- Use the given database to output the results of the following SQL queries: a.) SELECT DISTINCT C.buildingFROM Classroom AS CWHERE C.room number IN(SELECT S.room numberFROM Section AS SWHERE S.time slot id = A);Assistance with SQL statements Previous code; CREATE TABLE Lab4program_piershed ( code VARCHAR(5) PRIMARY KEY, name VARCHAR(20), tel VARCHAR(20));CREATE TABLE Lab4course_xxxx ( cid INT PRIMARY KEY, name VARCHAR(20), credits INT, mycode VARCHAR(5), FOREIGN KEY (mycode) REFERENCES Lab4program_xxxx(code)); 1. Insert 3 records into your Lab4program_xxxx table. The code should be "CPS", "TECH", "MATH", or "BIO". Please copy/paste your SQL statements with the output message in the text that shows you successfully insert 3 records to your table. 2. Insert 4 records into your Lab4course_xxxx table with at least 2 different mycode. Please copy/paste your SQL statements with the output message in the text that shows you successfully insert 4 records to your table./* Database Systems, 8th Ed., Rob/Coronel *//* Type of SQL : SQL Server */ CREATE TABLE CUSTOMER (CUST_NUM int,CUST_LNAME varchar(20),CUST_FNAME varchar(20),CUST_BALANCE float(8));INSERT INTO CUSTOMER VALUES('1000','Smith','Jeanne','1050.11');INSERT INTO CUSTOMER VALUES('1001','Ortega','Juan','840.92'); /* -- */ CREATE TABLE CUSTOMER_2 (CUST_NUM int,CUST_LNAME varchar(20),CUST_FNAME varchar(20));INSERT INTO CUSTOMER_2 VALUES('2000','McPherson','Anne');INSERT INTO CUSTOMER_2 VALUES('2001','Ortega','Juan');INSERT INTO CUSTOMER_2 VALUES('2002','Kowalski','Jan');INSERT INTO CUSTOMER_2 VALUES('2003','Chen','George'); /* -- */ CREATE TABLE INVOICE (INV_NUM int,CUST_NUM int,INV_DATE datetime,INV_AMOUNT float(8));INSERT INTO INVOICE VALUES('8000','1000','3/23/2010','235.89');INSERT INTO INVOICE VALUES('8001','1001','3/23/2010','312.82');INSERT INTO INVOICE VALUES('8002','1001','3/30/2010','528.10');INSERT INTO INVOICE VALUES('8003','1000','4/12/2010','194.78');INSERT INTO INVOICE…
- When writing queries in a programming language, why should we avoid creating a query by concatenating strings and instead use prepared statements or stored procedures in defense against SQL injection? a. concatenating strings helps prevent sql injection b. prepared statements or stored procedures help prevent the user/hacker from deliberately modifying the query by injecting sql instructions in the input values c. prepared statements prevent the query from taking as long to execute d. prepared statements enable the developer to just supply values without injecting sqlThis assignment is aimed at building an understanding of how to improve performance within databases by taking advantage the computers hardware by modifying MS SQL settings Prerequisites: Completion of Assignment 1B, reading of Module Readings and Slides. Run the following query to understand how much Memory is currently in use in the database: SELECT physical_memory_in_use_kb/1024 AS sql_physical_memory_in_use_MB, large_page_allocations_kb/1024 AS sql_large_page_allocations_MB, locked_page_allocations_kb/1024 AS sql_locked_page_allocations_MB, virtual_address_space_reserved_kb/1024 AS sql_VAS_reserved_MB, virtual_address_space_committed_kb/1024 AS sql_VAS_committed_MB, virtual_address_space_available_kb/1024 AS sql_VAS_available_MB, page_fault_count AS sql_page_fault_count, memory_utilization_percentage AS sql_memory_utilization_percentage, process_physical_memory_low AS sql_process_physical_memory_low, process_virtual_memory_low AS…QUESTION 18 The following SQL Query: SELECT partnameFROM quoteWHERE UPPER(suppliername) = 'TOOL TIME, INC.'; is MORE efficient than: suppliername = UPPER(suppliername);SELECT partnameFROM quoteWHERE suppliername = 'TOOL TIME, INC.'; because the second set of SQL commands uses two statements to turn the text into uppercase and then test it. a. True b. False