Question 1) F=16 kN single load, M=22 kN.m moment and w=11 kN/m distributed load are acting on the beam whose loading condition is given in the figure. The length L is also given as L=4 m. The cross-sectional properties of the beam are; body height yg=207 mm, body thickness xg=18 mm, flange width xf=182 mm, flange height yf=16 mm. Point E on the section is located just below the flange-body junction. It is desired to determine the stress state in the section taken from the C level of the beam. According to this; Question1-A) Find the normal force (NC) at point C. (Write your result in kN.) Question1-B) Find the shear force (VC) at point C. (Write your result in kN.) Question1-C) Find the bending moment (MC) at point C. (Write your result in kN.m.)

Refrigeration and Air Conditioning Technology (MindTap Course List)
8th Edition
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Chapter7: Tubing And Piping
Section: Chapter Questions
Problem 1RQ: The standard weight of copper tubing used most frequently in the heating and air-conditioning...
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Question 1) F=16 kN single load, M=22 kN.m moment and w=11 kN/m distributed load are acting on the beam whose loading condition is given in the figure. The length L is also given as L=4 m. The cross-sectional properties of the beam are; body height yg=207 mm, body thickness xg=18 mm, flange width xf=182 mm, flange height yf=16 mm. Point E on the section is located just below the flange-body junction. It is desired to determine the stress state in the section taken from the C level of the beam. According to this;

Question1-A) Find the normal force (NC) at point C. (Write your result in kN.)

Question1-B) Find the shear force (VC) at point C. (Write your result in kN.)

Question1-C) Find the bending moment (MC) at point C. (Write your result in kN.m.)

Question 1-D) Find the moment of inertia of the beam section. (Do your operations by converting the lengths to meters. Take at least 4 digits for the decimal part of your result and use the expression E for the decimal part. Write it as 5E-3 instead of 0.005.)

w kN/m
M kN.m
В
A
D
3
4
L
2L-
2L-
F kN
Xf
Yf
E
Yg
Xg
Yf
Xf
Transcribed Image Text:w kN/m M kN.m В A D 3 4 L 2L- 2L- F kN Xf Yf E Yg Xg Yf Xf
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