Question 14 d (tanh -'(cosx)) dx A cschx B) -csCx C) -secx D cothx

Q: | sin 5x cos 2x dx

A: We'll answer the first question only since the exact one wasn't specified. Please submit a new…

Q: sin 6x cos 3x dx

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Q: -83° sin (2x) cot (x) dx 370 csc (x)

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Q: State the half-angle identities used to integrate sin2 x and cos2 x.

A: Given, The functions are sin2 x and cos2 x

Q: Find the value →21. csc (sec- 2) + cos (tan¬1 (– V3))

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Q: السؤال 3 -Sec2 (). dx tan (5). · dz O ). de tan tan . da O ). dz O tan

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Q: (g) tan sec2 dx (c) sin“(3x) cos (3x) dx CoS'

A: Given: I1=∫sin43xcos33xdx, I2=∫tan4x2sec2x2dx

Q: 1 sec²x + tanx %3D tanx tanx

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Q: 11. cos4x-cos2 dx sin4x-cos2x

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Q: 6. cos x(csc x secx) secx) cotx

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Q: Find all exact solutions to the equation arcsin(2x)+arccos(x) 6 X=

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Q: cos(2x) dx sinx+cosx

A: Given: ∫cos(2x)sinx+cosxdx

Q: tanx . In(cosx) dx

A: we have to evaluate,   I=∫tanx . ln(cosx) dx

Q: Graph the equation for values of x between 0 and 720 In multiples of 30. y =5 sin(x)

A: Period of y=5sin(x) is 360 degree So between 0 to 720 degree, there are 720/360= 2 periods So we…

Q: 8. S sin 2x sin4xdx

A: put 2x=u so that dx=1/2 du.and solve the question.

Q: 6. G) sec 4 tan .3. dx 3 (),

A: Consider the given integration ∫tan6x3sec4x3dx

Q: 6. sech(4x) tan (4x) dx

A: We need to evaluate integral.

Q: 2- |1+ sin y dy

A: Given the integral is ∫1+sinydy

Q: 4, 8 sec3x tan5x dx

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Q: Sin 5x Cos 4x dx

A: The given integral is ∫sin5xcos4xdx.

Q: 15.sin2x secx- cscx =0

A: The value of x is π/4 + nπ/2

Q: tan (2x)sec (2x)dx 3

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Q: 1- 1- (Sin (coshx) sinhx dx

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Q: sec : tan/ sin :: cos :

A: As we know cos and sec are reciprocal of each other.  Therefore sec:tan/sin Then cos:sin/tan

Q: tan (x) + 1 dx =?

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Q: Evaluate the integral.

A: Given integral is ∫sin2xdx1+cos2x. Consider a=1+cos2x. Then da=-2cosxsinxdxdx=da-sin2x

Q: 2x y = Arc sec 3

A: We will use the formula of derivative of arc secx to solve this question.

Q: tan'x sec x - COS X %3D SBCX

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Q: tan 2x dx 2. S (3+ln cos 2x)6

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Q: 23. cos (3z + 4) dz 25. sec2 (3x + 2) dx

A: A

Q: If sinhx=-1÷2,then coshx is

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Q: (tan 2x + cot 2x)² dx

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Q: cos dx 5. Vaš sin² 3

A: Consider the integral: I=∫cos6x23dxx25sin23x23

Q: cos 6x cos 2x dx

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Q: The velocity of a particle moving along a line is ;2 – 2t sin(r2) meters per second. Then, the net…

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Q: ∫cos(15x)cos(4x)dx

A: Integration and differentiation can be considered as inverses of each other. Integration is mainly…

Q: 1. cos t (1 + tan²t) sin ß sec ß + cos ß csc ß 2.

A: Given : 1. cost1+tan2t2. sinβsecβ+cosβcscβ

Q: If y= sin-1 x, then y can terminate in quadrant ____ or ____.

A: Given: y=sin-1x We know that range of sin-1x is -π2,π2 So, y lies in either first quadrant or fourth…

Q: sin 5x cos 3x dx

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Q: 3. у %3D tan1(sinh 2x) Зсosh-1 (csc) 4. у %3 CSC

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Q: if sinx=1/8 and x is in quadrent 1, then cos(180-x)=???

A: Simplify cos(180-x),

Q: 6 sinx (cosx + 1)5 dx

A: We will find the value of definite integral as following.

Q: tan e de sece+ 4 cos € COS

A: The given integral is tan(phi)/[sec(phi)+4cos(phi)]

Q: —2х Se-2x sin 3x dx

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Q: Evaluate 0 -1 sin ¹(3x) dx.

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Q: fcox In(sinx) dx= fu du cotx In(sinx) dx = u du

A: In this question we substitute  u=lnsinx .

Q: Find sin 0 and tan 0 if the terminal side of 0 lies along the line y = -7x in QII. sin 0 = tan 0:

A: Given that terminal side of ϑ lies along the line y = -7x. Note that the slope of the line y = -7x…

Q: Sec tan (5x) dx

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Q: How do you differentiate y=arctan(cosx)?

A: The function given is