Question 2 A sand layer is of 5m depth and under it clay layer of 5m depth. Ysaturated sand = 20 kN/m² and Ysaturated clay = 19 kN/m2. The water table is at top of sand layer. If the water level drops by 3m but the zone above the water level is still saturated by capillary action then what is the effective stress at bottom of clay layer.
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- A soil profile consists of; layer 1, 10m sand layer and layer 2, 3m clay layer. The ground water table is located 4m below ground surface. For sand, γdry=2.00 T/m2 (tons/m2), γsat=2.25 T/m2, and for clay layer, LL=46%, water content=42% and Gs=2.76. A uniform vertical stress, ΔP=20T/m2 is applied at the ground surface. Determine, a) Effective unit weight of clay, b) overburden pressure at the mid point of the clay layer, c) primary consolidation settlementSituation 3:The water table in a certain deposit of soil is at a depth of 2m below the ground surface. The soil consists of clay up to depth of 4m from the ground and below which lies sand. The clay soil is saturated even above the water table:Clay strata: ? = 30%, ?? = 2.72Sandy Strata: ? = 26%, ?? = 2.64 1. Compute the total pressure.2. Compute the pore water pressure.3.Compute the effective stress pressure at a depth of 8m below the ground surface.A layer of sand, 4m thick, overlies a layer of low permeability clay, 5mthick. The bulk unit weight of the sand is 16.5 kN/m3 and its saturatedunit weight is 18 kN/m3 . The saturated unit weight of the clay is 21kN/m3 . The water table exists initially at 1.0m below ground level butpumping will permanently and rapidly lower the water table to 3.0mbelow ground level.Determine the variation of total stress and porewater pressure at depthh in the clay and the long-term variation in effective stress.Calculate the initial (before pumping) and the long-term (afterpumping) effective stress at the middle of the clay layer.
- Effective Stress in Soil Problem 1. The water table in a certain deposit of soil is at a depth of 2m below the ground surface. The soil consists of clay up to depth of 4m from the ground and below which lies sand. The clay soil is saturated even above the water table: Clay strata: ? = 30%,?? = 2.72 Sandy Strata: ? = 26%, ?? = 2.64 1. Compute the total pressure. 2. Compute the pore water pressure. 3. Compute the effective stress pressure at a depth of 8m below the ground surfaceA dense silt layer has the following properties: e =0.406 D10= 10.1 um Capillary constant = 0.209 sq.cm Free ground water level is 8m below the ground surface. 1.) Find the height of capillary rise in the siltin meters. 2) Find the vertical effective stress at 6m depth. Assume ys = 26.51 kn/m3 and the soil above capillary action rise and ground surface is partially saturated at 79%.A dense silt layer has the following properties.void ratio = 0.30eff. Diameter ?10 = 10??capillary constant (c)=0.20 cm²Groundwater level is 8.0m below the ground surface 1. Calculate the height of capillary rise in the silt. 2. Calculate the vertical effective stress in kpa at 5m depth, assume ?? = 26.5 ??/?³and that the soil above the capillary action rise and ground surface is partially saturated at 50%. 3. Calculate the effective vertical stress at 10m depth assuming ?? = 26.5 ??/?³and that the soil above the capillary action rise and ground surface is partially saturated at 50%.
- There is two layers of the soil The first layer is dry sand with the thickness of 8 m with dry unit weight of 18.0 kN/m3. The second layer is saturated sand with the thickness of 10 m with saturated unit weight of 20 kN/m3. The groundwater table is located at the top layer of the saturated sand. Determine the effective stress at the bottom of the saturated sand.A soil profile, under surcharge load of 25 kN/m2 at ground level, consists of 6m sand and 3m clay layer. Ground water table is 2m below sand layer. Dry unit weight and saturated unit weight of sand is 15.80kN/m3 and 16.90kN/m3 respectively. Clay layer, Gs=2.67 and saturated unit weight is 18.80 kN/m3. Determine a)Increase in stress at the mid layer of clay b) With dewatering 2m, what is the stress increase at the mid layer of clay c) How much must the water level be lowered to me more effective than the surcharged load?A clay formation having a depth of 4 m. underlies a sand formation having a depth of 3 m. The dry unit weight of sand is 16.5 kN/m3 and the saturated unit weights of clay and sand are 20.4 kN/m3 and 19.6 kN/m3 respectively. The groundwater table is at the interface of the sand and clay. Compute the effective stress in kPa at the bottom of the clay if water rises 2 m. above the ground surface.
- A 5-m depth of sand overlies a 6-m layer of clay, the water table being at the surface. The saturated unit weight of the sand is 19 kN/m3 and that of the clay is 20 kN/m3. Use the unit weight of water (?!) is 9.81 kN/m3. (a) Determine the total and effective vertical stresses at the centre of the clay layer. (b) The coefficient of lateral earth pressure at rest, ?", of the clay is identified as 0.8. Calculate the total and effective horizontal stresses at the centre of the clay layer.The water table in soil deposit is 2 m below the ground surface. The soil above the water table has dry unit weight of 14.85 kN/m^3. The saturated unit weight of the soil is 20.58 kN/m^3. Determine the total vertical stress, in kPa, at a point 4.8 m below the ground. Determine the total pore water pressure, in kPa, at a point 4.8 m below the ground. Determine the The effective vertical stress, in kPa, at a point 4.8 m below the ground.A clay layer 3.66 m thick rests beneath a deposit of submerged sand of 7.92 m thick. The top of the sand is located 3.05 m below the surface of a lake. The saturated unit weight of the sand is 19.62 kN/m3 and of the clay is 18.36 kN/m3. Compute (a) the total pressure (b) the pore water pressure and (c) the effective pressure all at the mid height of the clay layer. Draw the figure