Question 2: derive 0 = 1/2at2 + wot Oo- You may use prior derived results.

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter1: Units And Measurement
Section: Chapter Questions
Problem 33P: In SI units, speeds are measured in meters per second (m/s). But, depending on where you live,...
icon
Related questions
icon
Concept explainers
Topic Video
Question
The Notion of Deriving
Deriving an equation (or a statement) is more than just asserting it. It's
showing how it must be true (and anything contrary must be false).
One doesn't understand the material as long as one is limited to
memorizing statements or equations, without being able to connect
them.
As a further, practical thing, understanding the connection makes it less
likely that one would use an equation when it doesn't apply. In
particular, one would avoid the "equations of constant acceleration"
anytime one had non-constant acceleration.
In this assignment, I assign you to derive the "equations of constant
acceleration" -- all but one that I will derive. We will use 0, w, and a,
satisfying these definitions:
dw
de
and
a =
dt
W =
dt
and one special case: a is constant. (You should spot the false step
when a is non-constant.) w and 0 are functions of time: w(t) and 0(t).
ωο- ω(0), and θ0-θ(0).
My Example: derive w2 - wo? = 2a(0-0).
dw
dw de
dw
a =
dt
de dt
de
Multiply by dt and integrate:
Sado
w dw = w?
d0 = a0 + C =
w?
2a0 + 2C
Substitute the initial (t=0) quantities, and subtract. The constant of
integration vanishes.
w3 = 2a0 + 2C
w? – w = 2a(0 – 0o)
The e integration fails if a is non-constant. There is also a type of
situation where the step before the integration fails, involving w.
Transcribed Image Text:The Notion of Deriving Deriving an equation (or a statement) is more than just asserting it. It's showing how it must be true (and anything contrary must be false). One doesn't understand the material as long as one is limited to memorizing statements or equations, without being able to connect them. As a further, practical thing, understanding the connection makes it less likely that one would use an equation when it doesn't apply. In particular, one would avoid the "equations of constant acceleration" anytime one had non-constant acceleration. In this assignment, I assign you to derive the "equations of constant acceleration" -- all but one that I will derive. We will use 0, w, and a, satisfying these definitions: dw de and a = dt W = dt and one special case: a is constant. (You should spot the false step when a is non-constant.) w and 0 are functions of time: w(t) and 0(t). ωο- ω(0), and θ0-θ(0). My Example: derive w2 - wo? = 2a(0-0). dw dw de dw a = dt de dt de Multiply by dt and integrate: Sado w dw = w? d0 = a0 + C = w? 2a0 + 2C Substitute the initial (t=0) quantities, and subtract. The constant of integration vanishes. w3 = 2a0 + 2C w? – w = 2a(0 – 0o) The e integration fails if a is non-constant. There is also a type of situation where the step before the integration fails, involving w.
Question 2: derive 0 = 1/2at² + wot
+ 0o-
You may use prior derived results.
Transcribed Image Text:Question 2: derive 0 = 1/2at² + wot + 0o- You may use prior derived results.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Displacement, velocity and acceleration
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
University Physics Volume 1
University Physics Volume 1
Physics
ISBN:
9781938168277
Author:
William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:
OpenStax - Rice University