QUESTION 2: How much Pareactant will be needed to produce 105.8g of tetraphosphorus decaoxide (P4010)? G: 105.8g P4010 мM: 1 тol Pa010 — 287.88g Р,010 1 mol P4 = 127.88g P4 MR: 3 тol P,01о — Зтоl Р, СHOICES: A. 74g P4 B. 0.74g P4 С. 47g Ра D. 0.047g P4
QUESTION 2: How much Pareactant will be needed to produce 105.8g of tetraphosphorus decaoxide (P4010)? G: 105.8g P4010 мM: 1 тol Pa010 — 287.88g Р,010 1 mol P4 = 127.88g P4 MR: 3 тol P,01о — Зтоl Р, СHOICES: A. 74g P4 B. 0.74g P4 С. 47g Ра D. 0.047g P4
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.61PAE: 4.61 What is actually measured by the octane ratings of different grades of gasoline?
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