Question 2.An array containing the given n-element integers and the sum of the consecutive elements in the aray with the integer k Find how many of them are divisible without remainder to the given integer k. • The array contains n elements ( array = [array [(0], array (1..., array (n-1]] ). •k is a positive integer • Sum of consecutive elements for any ( first , next ) pair array (first] + array (next] if o first
Question 2.An array containing the given n-element integers and the sum of the consecutive elements in the aray with the integer k Find how many of them are divisible without remainder to the given integer k. • The array contains n elements ( array = [array [(0], array (1..., array (n-1]] ). •k is a positive integer • Sum of consecutive elements for any ( first , next ) pair array (first] + array (next] if o first
Computer Networking: A Top-Down Approach (7th Edition)
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![Question 2.An array containing the given n-element integers and the sum of the consecutive elements in the aray with the integer k
Find how many of them are divisible without remainder to the given integer k.
• The array contains n elements ( array = [array [(0], array (1..., array (n-1]] ).
•k is a positive integer
• Sum of consecutive elements for any ( first , next ) pair
array (first] + array (next] if o first <next
Write the Java code that returns the result for the integer array (array) and integer (k) entered in this context.
V Define the section to be caleulated as the Java object (" Question2 ").
V Question2 ; Take the note string as input.
o public Question2 ( int [] input )
V Take the value of " k" as input in the " countSumPairs " method to calculate and how many
retum the sum of the pairs is divided by the value "k" without any remainder.
o public int countSumPairs ( int k )
Code sample:
public class Question2 {
public Question2 ( int [] input ) {
I/ Complete the countSumPairs function below
public int countSumPairs ( int k ) (
For example: Let us assume that an array of positive integers looks like this:
If Numbers = {1, 3, 2, 6, 1, 2} and k = 3 , the output will be given on the screen.
• (0, 2) → array (0] + array [2] = 1 + 2 = 3
• (0, 5) → array [0] + array [5] = 1 + 2 = 3
•(1, 3) → array [1] + array [3] = 3 + 6 = 9
•(2, 4) → array [2] + array [4] = 2 + 1 = 3
• (4, 5) → array [4] + array [5] = 1 + 2 = 3
A total of 5 element pairs were found for the value k = 3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3eacafd0-3d51-4862-88c0-44f6dbc374ce%2F1bbee1c7-ef40-41f9-92e1-e3886d735428%2F69q15cm_processed.png&w=3840&q=75)
Transcribed Image Text:Question 2.An array containing the given n-element integers and the sum of the consecutive elements in the aray with the integer k
Find how many of them are divisible without remainder to the given integer k.
• The array contains n elements ( array = [array [(0], array (1..., array (n-1]] ).
•k is a positive integer
• Sum of consecutive elements for any ( first , next ) pair
array (first] + array (next] if o first <next
Write the Java code that returns the result for the integer array (array) and integer (k) entered in this context.
V Define the section to be caleulated as the Java object (" Question2 ").
V Question2 ; Take the note string as input.
o public Question2 ( int [] input )
V Take the value of " k" as input in the " countSumPairs " method to calculate and how many
retum the sum of the pairs is divided by the value "k" without any remainder.
o public int countSumPairs ( int k )
Code sample:
public class Question2 {
public Question2 ( int [] input ) {
I/ Complete the countSumPairs function below
public int countSumPairs ( int k ) (
For example: Let us assume that an array of positive integers looks like this:
If Numbers = {1, 3, 2, 6, 1, 2} and k = 3 , the output will be given on the screen.
• (0, 2) → array (0] + array [2] = 1 + 2 = 3
• (0, 5) → array [0] + array [5] = 1 + 2 = 3
•(1, 3) → array [1] + array [3] = 3 + 6 = 9
•(2, 4) → array [2] + array [4] = 2 + 1 = 3
• (4, 5) → array [4] + array [5] = 1 + 2 = 3
A total of 5 element pairs were found for the value k = 3.
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