Question 3: A list can be reversed using .reverse (). However, suppose we have a list whose entries might also be lists, and those lists can further contain lists, etc., and we want to reverse ALL the lists at all levéls. Write à recursive function called total reverse that does this, returning a new list with itself reversed and every list contained inside it reversed. Example output: >>> L1 = [1, [3, 4], 16, [21, 42, [65, 77]], 0] >>> L2 = total_reverse (L1) >>> print (L2) [0, [[77, 65], 42, 21], 16, [4, 3], 1]
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#python code
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- python code Write a recursive function such that, given a list of intergers (say v) and an integer value (say x), the function returns resulting subset if there is a subset of intergers in v that sum up to x. Otherwise the function returns an empty list; Also write a sample code that runs this function using an example list and value x, and state the expected resultIn Kotlin, Write a recursive function called myZip, with an expression body. MyZip takes two Lists and returns a List of Pairs in which each value may be any type (I suggest your start by thinking out how to represent this data type). The pairs consist of corresponding elements in the two lists (the first element of the first list and the first element of the second list, etc). The base case should be that either (or both) of the original lists has length 1, so that, if the lists have different length, the zipping stops when the first list runs out of values.Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…
- The goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.‘Write a function nesting(), which takes an arbitrary number of parameters, and returns a list containing the arguments. Write another function unnesting(), which takes a list L as the parameter and retums a 1D list. Notice that, you should be able to use loops to solve thisproblem and should not use recursive functions (which we will not cover in this course). ‘Write assertions to test the two functions.For example nesting(1, nesting(2, 3, nesting(4, 5, [6])), [7, 8], 9)unnesting([1, [2, 3, [4, 5, [6]]], [7. 8], 9]) (1, [2, 3, [4, 5, [6]]], [7, 8], 9][1, 2,3, 4, 5, 6, 7, 8 9]The Binary Search algorithm works by testing a mid-point, then eliminating half of the list. In this exercise, you are going to take our binary search algorithm and add print statements so that you can track how the search executes. Inside of the recursive binary search function, add print statements to print out the starting, ending, and midpoint values each time. Then as you test a value, print out the results, either too high, too low, or a match. Sample Output Starting value: 0 Ending value: 9 Testing midpoint value: 4 Too high! Starting value: 0 Ending value: 3 Testing midpoint value: 1 Too low! Starting value: 2 Ending value: 3 Testing midpoint value: 2 Match!
- I just need the method they are asking for Write a recursive function that takes a start index, array of integers, and a target sum. Your goal is to find whether a subset of the array of integers adds up to the target sum. The start index is initially 0.A target sum of 0 is true for any array. Examples: subsetSum(0, {2, 4, 8}, 10) -> true public boolean subsetSum(int start, int[] nums, int target) { }(This question is for a linked list of the type described on the front page, Item 5). Write a recursive function CountGE60. that receives a linked list (may or may not be empty) and returns the number of nodes (each containing a data item value) greater than or equal to 60.In Kotlin A. Write a function lengthGreaterThan() with an expression body that takes a String s and an Int n and returns true if the String is at least n characters long. Then revise the function so that it can accept null values. If it receives null as the parameter, it should return false. B. Write a recursive function with an expression body that takes a list of nullable Strings and and Int an returns a list of just the Strings from the original list for which the function you wrote in the first part returns true C. Get the same result as in part B by using filter()
- Write a function in a racket code that takes as input a list of elements and returns a list with elements and their position after. For example, if the input to the function is (list ’a ’b ’c) then it will return (list a 1 b 2 c 3). Make sure to use recursionBelow,enter code to complete implementation of a recursive function sum_all_integers(), which takes an input n and adds all intergers preceding it, up to n: add_all_integers(n):In Clojure In the following expression, there are three missing symbols (marked with underscores). (defn length [l] (if (empty? l) _ ( _ 1 ( _ (rest l))))) We want length to be a function which returns the number of elements in a list. Assume we are writing this function definition using recursion, what should be filled in in each of these underlined blanks?