Question 3 Let M = {{90, 91, 92}, {a}, 90, fs, {9₁}}, where f, is defined as follows: i. ii. iii. fs (90, a) = 9₁ fs (9₁, a) = 92 fs (2, a): = 92 Deterministic Finite Automata is a quintuple of M = {S, I, qo, fs, F}, where; S the finite states I→ the input alphabet qo the initial states f→ the state transition function F→ the final states State the elements that involve in M. Construct a transition table for the DFA given based on 1 (i). Shows the transition diagram that is extracted from 1 (ii)

Question 3 Let M = {{90, 91, 92}, {a}, 90, fs, {9₁}}, where f, is defined as follows: i. ii. iii. fs (90, a) = 9₁ fs (9₁, a) = 92 fs (2, a): = 92 Deterministic Finite Automata is a quintuple of M = {S, I, qo, fs, F}, where; S the finite states I→ the input alphabet qo the initial states f→ the state transition function F→ the final states State the elements that involve in M. Construct a transition table for the DFA given based on 1 (i). Shows the transition diagram that is extracted from 1 (ii)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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In this problem, we only consider automata without epsilon transitions. A clipping of an NFA N is a DFA obtained by the following process: for each state-letter pair (q, x) where q ∈ Q, x ∈ Σ, if |δ(q, x)| > 1, choose one element of it to be δ(q, x) and ignore the rest. Note that an NFA may have many possible clippings. 1. Consider the following claim: “For every epsilon-free NFA N and string x, the NFA N accepts x if and only if some clipping of N accepts x.” This claim is false. Show that it is false by providing a counterexample. (Aside: It turns out that deciding whether N accepts x is in P, while deciding whether some clipping of N accepts x is NP-complete, which you will learn about later in the course. Hence, if the claim were true, it would imply that P = NP.) An automaton A over the alphabet Σ is universal if it accepts every string, that is, if L(A) = Σ∗. 2. Consider the following claim: “For every epsilon-free NFA N, the NFA N is universal if and only if some clipping…
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