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- What is the leading term for the following expressions and specify the lowest Big O Complexity for each algorithm?Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Output FormatOutput a single line containing the fastest time to get to square N from square 1. Sample Input 05 2 1 4 13 Sample Output 06 Explanation 0The optimal answer is to: RUN to square 2 (+2 seconds). Sonic now has 1 energy. DASH to square 3 (+1 second). Sonic now has 0 energy. RUN to square 4 (+2 seconds). Sonic now has 1 energy. DASH to square 5 (+1 second). Sonic now has 0 energy. Total time is 6 seconds. Sample Input 15 4 2 10 0 Sample Output 112 Explanation 1The optimal answer is to: RUN to square 2 (+4 seconds). Sonic now has 1 energy. RUN to square 3 (+4 seconds). Sonic now has 2 energy. DASH to square 4 (+2 seconds). Sonic now has 1 energy.…The doubling test will result in the hypothesis that the running time is a N for a constant a when an algorithm's order of development is N log N. Is that an issue, then?
- Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply divide-and-conquer algorithm in the problem. Make sure all test cases return expected outputs. Hint: Apply bisection method/modules Output FormatOutput contains a line with two space-separated integers W_a and W_b.- W_a is the maximum matchups won by Hamiltonia- W_b is the maximum matchups won by Burrgadia. Sample Input 03 554402410 Sample Output 03 0 Sample Input 15 4833485183 Sample Output 12 2 Sample Input 27 81028121912601319851 Sample Output 27 0 The actual code """Solves a test case Parameters:a : int - number of leaders in Hamiltoniab : int - number of leaders in Burrgadias_i : array-like - rap proficiencies of Hamiltonia's leadersr_j : array-like - rap proficiencies of Burrgadia's leaders Returns:win_a : int - number of…What is the worse-case complexity scenario for the following snippets of code? Please show the breakdown of your calculations.Two loops in a row: A nested loop in which the number of times the inner loop executes depends on the value of the Outer loop index. For ( I = 0; I < N; i++) { For ( j = N; j > I; j- - ) { Sequence of statements } }c. How many times is the basic operation executed?d. What is the efficiency class of this algorithm?e. Suggest an improvement, or a better algorithm altogether, and indicate itsefficiency class. If you cannot do it, try to prove that, in fact, it cannot bedone.
- I'm trying to understand how both of these algorithms, separated by a) and b), have a time complexity of O(n), could you explain how this is? a)int i = 0;while (i < n) { ... i++;}for(int j = 3; j < n * n; j += n) { ...}int k = 1;while (k < n) { ... k *= 2;} b)for(int i = 1; i < n; i += 3) { for(int j = 3; j < 10; j++) { for(int k = 5; k < n; k += n) { ... } }}Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion/memoization. Make sure ALL test cases return expected outputs. Sample Input 04 412340123 Sample Output 013715 Explanation 0You are given the sequence 1,2,3,4.F0 = A0 = 1F1 = A1 + F0 = 2 + 1 = 3F2 = A2 + F1 + F0 = 3 + 3 + 1 = 7F3 = A3 + F2 + F1 + F0 = 4 + 7 + 3 + 1 = 15 The actual code def solve(k,a): MOD = 1000000007 # compute and return answer here q, n = list(map(int,input().rstrip().split(" ")))a = [int(input().rstrip()) for i in range(n)]outs = []for i in range(q): k = int(input().rstrip()) outs.append(solve(k,a))print("{}".format("\n".join(list(map(str,outs)))))Write an efficient algorithm for the following problem (either pseudocode or java), and describe your reasoning. Determine the Time complexity and if you cannot find any polynomial time algorithm, then give a backtracking algorithm. Problem will be on repeat numbers input will be ARRAY[1,2, ... , n] number of positive numbes. Output will any one number that is repeated more than n/3 times. for example, if you have [1,1,2,2,2,1], since n = 6 and n/3 = 2, both 1 and 2 showed up more than n/3 times. the output will be either 1 or 2 (just one of the values are required) if you have [1,1,3,4,5,6,7,8,9], since 1 is only repeated twice, and n/3 = 3, output will be "none"
- Precisely specify the conditions under which the following algorithm returns True, and then discuss, in detail, the running time of the algorithm. If you think it has different best- and worst-case running times then these should be considered separately, and you should explain the conditions under which best and worst-cases arise.Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Sample Input 0:5 20011014 Sample Output 0:1 1 Explanation 0:The best way to jump from square 1 to square 5 is by jumping 4 squares. That requires only 1 jump.In fact, that is the only solution, thus the second output is 1. Sample Input 1:6 3010100123 Sample Output 1:2 2 Explanation 1The best sequence is to jump 2 squares to square 3 then 3 squares to end in square 6.This is one solution. The other solution is to jump from 1 -> 3 -> 5 -> 6. These are the only two solutions, therefore the second output is 2. Sample Input 2:7 2000110037 Sample Output 2:-1 0 Explanation 2:It is impossible to reach square 7 with the specified jump values. The actual…Please give the big-O time complexity of the following snippet of code and state the reason why it is so. I'll give upvote if correct, thank you.
